All categories

2 years ago

Someone please help me w this .

Mathematics

2 answers:

Varvara68 [4.7K]2 years ago

5 0

Answer:

the second one

Step-by-step explanation:

Alex73 [517]2 years ago

4 0

It’s (5,7) given that I don’t care equal 25 so help me so I can help you

You might be interested in

How do you write 20/10 as a mixed number

jolli1 [7]

It does not equal a mixed number, but a whole number so write 2 instead of a mixed number.

5 0

2 years ago

Find the area of the parallelogram.

tensa zangetsu [6.8K]

Answer:

Step-by-step explanation:

Area of a parallelogram = base × height

From the question

The base is = 30 cm

Let h represent the height of the parallelogram

We must first use Pythagoras theorem to find the height of the parallelogram before finding it's area

We have

${25}^{2} = {h}^{2} + {24}^{2} \\ {h}^{2} = {25}^{2} - {24}^{2} \\ {h}^{2} = \sqrt{ {25}^{2} - {24}^{2} } \\ {h}^{2} = \sqrt{625 - 576} \\ {h}^{2} = \sqrt{49}$

We have the answer as

h = 7 cm

So from the question

height = 7cm

Let's substitute the base and the height into the above formula and solve for the area

We have

Area = 30 × 7

We have the final answer as

Hope this helps you

5 0

2 years ago

If Anna can run 2km in 8 min, how long will it take her to run 5 km if she maintains her speed

rodikova [14]

Answer:

20 minutes

Step-by-step explanation:

Find the speed per km. 2km/8min. This is 4 minutes per km.

Next, multiply the minutes per km by km. 4 min x 5 km.

This equals 20 :)

5 0

2 years ago

What is the largest number that can be rounded to 2500 when rounded to the nearest ten

Nookie1986 [14]

2499.9999999... is your answer

hope this helps

3 0

2 years ago

Read 2 more answers

Which equation represents a circle with a center at (2,-3) and a radius of 11

Verdich [7]

Answer:

x^2-4x+y^2+6y-108=0

Step-by-step explanation:

$The- equation- of- circle- with -center- at- (h,k) -and -a -radius- of- r -is: \\(x-h)^2 +(y-k)^2 = r^2\\h = 2 , \\ k = -3\\r = 11\\(x-2)^2+(y-(-3))^2 = 11^2\\(x-2)^2+(y+3)^2 = 121\\x^2-4x+4 +y^2+6y+9 = 121\\x^2 -4x+y^2+6y+4+9=121\\x^2 -4x+y^2+6y+13=121\\x^2 -4x+y^2+6y=121-13\\x^2 -4x+y^2+6y= 108\\x^2 -4x+y^2+6y-108 = 0$

8 0

3 years ago