Complete question is;
A model for a company's revenue from selling a software package is R = -2.5p² + 500p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.
Answer:
Price to maximize revenue = $100
Maximum revenue = $25000
Step-by-step explanation:
We are told that:
R = -2.5p² + 500p, where p is the price in dollars of the software.
The maximum revenue will occur at the vertex of the parabola.
Thus, the price at this vertex is;
p = -b/2a
Where a = - 2.5 and b = 500
Thus:
p = -500/(2 × -2.5)
p = -500/-5
p = 100 in dollars
Maximum revenue at this price is;
R(100) = -2.5(100)² + 500(100)
R(100) = -25000 + 50000
R(100) = $25000
Answer:
see below
Step-by-step explanation:
GET ≅MAP
Then
<G = <M
<E = <A
<T = <P
GE = MA
ET = AP
GT = MP
by corresponding parts of congruent triangles are congruent
Answer:
n=4
Step-by-step explanation:
7n-3n=16
4n=16
n=16/4
n=4
Answer:
..........uh ok but u do know that u need to answer questions and get points to talk to users....right..?
A) 3
the reason is because $225 a night and $75 a day 75*2 is 175 so then you add 175+225 is 400 multiple it by 3 your answer is $1200 enjoy your answer
