How to I do this problem ?

Rand has 10 points. Randy has 8 points. how many more does Rand have than Randy?

Harlamova29_29 [7]

Answer:

2 more than Randy.

Step-by-step explanation:

You need to subtract to get your answer so you subtract 10 and 8 giving you your answer of 2 more points.

3 0

4 years ago

Read 2 more answers

If anyone knows about definite integrals for calculus then please I request help! I

kicyunya [14]

Answer:

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Set u: $\displaystyle u = 4x^{-2}$
[u] Differentiate [Basic Power Rule, Derivative Properties]: $\displaystyle du = \frac{-8}{x^3} \ dx$
[Bounds] Switch: $\displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.$

Step 3: Integrate Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx$
[Integral] U-Substitution: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du$
[Integral] Exponential Integration: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}$
Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)$
Simplify: $\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0

3 years ago

Simplify. 4n + 12 + 7n A. 4 n + 19 B. 23 n C. 16 n + 7 D. 11 n + 12

Darina [25.2K]

Answer:

D. 11n + 12

Step-by-step explanation:

You can simplify the 4n + 7n to be 11n by adding them together.

This means the answer is 11n + 12.

8 0

2 years ago

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A=5/6(B+C) SOLVE FOR C

Shalnov [3]

A = 5/6(B + C)

multiply 6 on both sides

6A = 5(B + C)

divide 5 from both sides

6A/5 = B + C

subtract B from both sides

6A/5 - B = C

3 0

3 years ago

0.25 r – 0.125 + 0.5 r = 0.5 + r . solve for r

Ivahew [28]

First, we need to get all of the r's on the same side. To do this, we need to subtract "r" from both sides.

0.25r - 0.125 + 0.5r - r = 0.5 + r - r

0.25r - 0.125 +0.5r - r = 0.5

Now, we need to add like terms.

0.25r + 0.5r - r - 0.125 = 0.5

-0.25r - 0.125 = 0.5

Now, we need to get the "r" variable by itself.

-0.25r - 0.125 + 0.125 = 0.5 + 0.125

-0.25r = 0.625

Now, we divide both sides by -0.25

(-0.25r) / (-0.25) = 0.625 / (-0.25)

r = -2.5

6 0

4 years ago