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Vaselesa [24]
3 years ago
11

PLS HALP ASAP points

Chemistry
1 answer:
marishachu [46]3 years ago
5 0

Answer:

50 N ( left)

Explanation:

Given data:

The force on right side = 450 N

The force on left side = 500 N

Net force = ?

Solution:

F (net) = 500 N - 450 N

F (net) =  50 N ( left)

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You are given a sample resembling silver. Which of the following properties could be used to help determine whether the sample i
defon

Answer:

the density of the sample - the melting point of the sample

Explanation:

Intrinsic property is the property of matter which exists itself or within subject. In other words, it do not depend on the mass of the sample. An extrinsic property is not inherent or essential to subject which is being characterized. In other words, it depend on the mass of the sample.

For example,

Density, melting point are example of intrinsic property. Whereas, weight, volume are an example of extrinsic property.

Intrinsic properties helps to determine the matter. Thus, density of sample and melting point of sample is the answer.

5 0
3 years ago
Calculate the mass percentage of oxygen in dry air
grigory [225]
              <span> (0.20948 x 31.998) / (
(0.78084 x 28.013) +
(0.20948 x 31.998) +
(0.00934 x 39.948) +
(0.000375 x 44.0099) +
(0.00001818 x 20.183) +
(0.00000524 x 4.003) +
(0.000002 x 16.043) +
(0.00000114 x 83.80) +
(0.0000005 x 2.0159) +
(0.0000005 x 44.0128) ) = 0.23140 = 23.140% O by mass </span>
5 0
4 years ago
Read 2 more answers
Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve
Anton [14]
For the answer to the question above,
1∙5µm² = ? m² 
1m * 1m = 1m²     But 1m = 1,000,000µm = 1x 10^6µm   1x10^6µm * 1x10^6µm = 1m²      1x 10^12µm² = 1m² (Now, try dividing both sides by 1x10^12).   1x10^12µm² /(1x10^12) = 1m² /(1x10^12)    1µm² = 0∙000 000 000 001 m² (multiply both sides by by 1∙5).    1∙5µm² = 0∙000 000 000 0015 m²   

 1∙5µm² = 1∙5x 10^-12 m²
I hope this helps
7 0
4 years ago
If Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?
Fiesta28 [93]
The given sentence is part of a longer question.

I found this question with the same sentence. So, I will help you using this question:

For the reaction N2O4<span>(g) ⇄ 2NO</span>2(g), a reaction mixture at a certain temperature initially contains both N2O4 and NO2 in their standard states (meaning they are gases with a pressure of 1 atm<span>).  If </span>Kp = 0.15, which statement is true of the reaction mixture before any reaction occurs?


(a) Q = K<span>;   The reaction </span>is at equilibrium.
(b) Q < K<span>;   The reaction </span>will proceed to the right.
(c) Q > K<span>;   The reaction </span>will proceed to the left.

The answer is the option (c) Q > K<span>; The reaction will proceed to the </span>left, since Qp<span> = </span>1<span>, and 1 > 0.15.</span>
Explanation:

Kp is the equilibrium constant in term of the partial pressures of the gases.

Q is the reaction quotient. It is a measure of the progress of a chemical reaction.

The reaction quotient has the same form of the equilibrium constant but using the concentrations or partial pressures at any moment.

At equilibrium both Kp and Q are equal. Q = Kp

If Q < Kp then the reaction will go to the right (forward reaction) trying to reach the equilibrium,

If Q > Kp then the reaction will go to the left (reverse reaction) trying to reach the equilibrium.

Here, the state is that both pressures are 1 atm, so Q = (1)^2 / 1 = 1.

Since, Q = 1 and Kp = 0.15, Q > Kp and the reaction will proceed to the left.
6 0
4 years ago
In which process are glucose and oxygen the reactants?
Alenkasestr [34]
The answer is B. Cellular Respiration, for sure.
7 0
4 years ago
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