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Vaselesa [24]
2 years ago
11

PLS HALP ASAP points

Chemistry
1 answer:
marishachu [46]2 years ago
5 0

Answer:

50 N ( left)

Explanation:

Given data:

The force on right side = 450 N

The force on left side = 500 N

Net force = ?

Solution:

F (net) = 500 N - 450 N

F (net) =  50 N ( left)

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7) What is the hydrogen concentration of a solution with a pH of 2.1? *
lesya [120]

Answer:

Hydrogen concentration = 7.94×10^-3 M

Explanation:

from potenz Hydrogen ( pH ) definition

pH = -log[H+]

2.1 = -log[H+]

2.1/-log = -log[H+]/-log

10^-2.1 = [H+]

[H+] = 7.94×10^-3M

8 0
3 years ago
What are the coefficients for the following reaction when it is properly balanced? ?potassium iodide +?lead (II) acetate lead (I
xeze [42]

Answer: none of the above

Explanation:

It should be 2,1,1,2 to give a balanced chemical reaction

7 0
3 years ago
How is it possible to change the shape of your molecular models without breaking any of the covalent bonds?
horrorfan [7]

Answer:

A molecule's shape strongly affects its physical properties and the way it interacts with other molecules, and plays an important role in the way that biological molecules (proteins, enzymes, DNA, etc.) interact with each other.

Explanation:

5 0
2 years ago
Please give me the answer please
zepelin [54]

Answer:

A. 30cm³

Explanation:

Based on the chemical reaction:

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

<em>1 mol of calcium carbonate reacts with 2 moles of HCl to produce 1 mol of CO₂</em>

<em />

To solve this question we must convert the mass of each reactant to moles. With the moles we can find limiting reactant and the moles of CO₂ produced. Using PV = nRT we can find the volume of the gas:

<em>Moles CaCO₃ -Molar mass: 100.09g/mol-</em>

1.00g * (1mol / 100.09g) = 9.991x10⁻³ moles

<em>Moles HCl:</em>

50cm³ = 0.0500dm³ * (0.05 mol / dm³) = 2.5x10⁻³ moles

For a complete reaction of 2.5x10⁻³ moles HCl there are necessaries:

2.5x10⁻³ moles HCl * (1mol CaCO₃ / 2mol HCl) = 1.25x10⁻³ moles CaCO₃. As there are 9.991x10⁻³ moles, HCl is limiting reactant.

The moles produced of CO₂ are:

2.5x10⁻³ moles HCl * (1mol CO₂ / 2mol HCl) = 1.25x10⁻³ moles CO₂

Using PV = nRT

<em>Where P is pressure = 1atm assuming STP</em>

<em>V volume in L</em>

<em>n moles = 1.25x10⁻³ moles CO₂</em>

<em>R gas constant = 0.082atmL/molK</em>

<em>T = 273.15K at STP</em>

<em />

V = nRT / P

1.25x10⁻³ moles * 0.082atmL/molK*273.15K / 1atm = V

0.028L = V

28cm³ = V

As 28cm³ ≈ 30cm³

Right option is:

<h3>A. 30cm³</h3>

5 0
3 years ago
Filtration can separate a mixture of fine sand and coarse gravel. The holes in the filter should be large enough to allow ______
Charra [1.4K]

The sand to pass through, but not the gravel. Hope this helps!

5 0
2 years ago
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