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BigorU [14]
3 years ago
5

In the reaction of nitrogen with hydrogen to produce ammonia, NH3, how many moles of ammonia would be produced from 1.0 mol of h

ydrogen and excess nitrogen?
N2 + 3 H2 --> 2 NH3

0.33 mol
0.67 mol
2.0 mol
1.3 mol
Chemistry
2 answers:
Lina20 [59]3 years ago
7 0
N2 + 3H2 ------> 2NH3
According to the equation;
3 mol of hydrogen will produce 2mol of ammonia.
1 mol of hydrogen _____________________?

= 2 × 1/3

= 0.67 mol
Strike441 [17]3 years ago
7 0

Answer:

0.67 mol

Explanation:

Given data:

Number of moles of ammonia produced = ?

Number of moles of hydrogen = 1.0 mol

Amount of nitrogen = excess

Solution:

Chemical equation:

N₂ + 3H₂   →       2NH₃

Now we will compare the moles of ammonia with hydrogen.

                       H₂            :           NH₃

                         3             :            2

                       1.0             :        2/3×1.0 = 0.67

Thus, from 1.0 mole of hydrogen 0.67 moles of ammonia will produced.

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If you start with 6 moles of N2 and 6 moles of H2 (meaning you won't have enough of 1 of the ingredients), how many moles of NH3
Ivahew [28]

Answer:

4molNH_3

Explanation:

Hello there!

In this case, according to the given information it will be firstly necessary to set up the chemical equation taking place:

N_2+3H_3\rightarrow 2NH_3

We infer we need to calculate the moles of NH3 by using both of the moles of N2 and H2 at the beginning, in order to identify the limiting reactant:

n_{NH_3}=6molN_2*\frac{2molNH_3}{1molN_2}=12molNH_3\\\\ n_{NH_3}=6molH_2*\frac{2molNH_3}{3molH_2}=4molNH_3\\

Thus, since hydrogen yields the fewest moles of ammonia, we conclude that we are just able to yield 4 moles of NH3.

Regards!

8 0
3 years ago
Heres a easy question......
stiv31 [10]
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A weather balloon is filled with helium that occupies a volume of 500 L at 0.995 atm and 32.0 ℃. After it is released, it rises
Yuki888 [10]

Answer : The volume of the balloon at the new location is, 591.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.995 atm

P_2 = final pressure of gas = 0.720 atm

V_1 = initial volume of gas = 500 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 32.0^oC=273+32=305K

T_2 = final temperature of gas = -12^oC=273+(-12)=261K

Now put all the given values in the above equation, we get:

\frac{0.995atm\times 500L}{305K}=\frac{0.720atm\times V_2}{261K}

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3 0
4 years ago
Methanol is the simplest alcohol. How are larger alcohol molecules formed?
bazaltina [42]

Answer:

Methanol, also known as methyl alcohol amongst other names, is a chemical with the formula CH₃OH. It is a light, volatile, colourless, flammable liquid with a distinctive alcoholic odour similar to that of ethanol.

Explanation:

7 0
3 years ago
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vivado [14]

Answer:

CH₄ will diffuse at faster rate.

Explanation:

According to Graham's law,

The rate of diffusion is inversely proportional to the square root of molar mas of gas.

It  is given in question the molar mass of CH₄ is 16 g. Thus the square rot of 16 is.

√16 = 4

The molar mass of SO₂ is 64 g and the square root is,

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As it is stated that diffusion rate is inversely related to the square root of molar mass thus the diffusion rate of  SO₂ is lower while methane diffuse faster.

8 0
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