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Lena [83]
3 years ago
6

(05.02 MC)

Chemistry
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

Mass = 365.45 g

Explanation:

Given data:

Number of moles of HNO₃ = 5.8 mol

Mass of HNO₃ = ?

Solution:

Formula:

Mass = number of moles × molar mass

Molar mass of HNO₃ = 63.01 g/mol

by putting values,

Mass = 5.8 mol ×  63.01 g/mol

Mass = 365.45 g

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A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t
kotegsom [21]

<u>Given:</u>

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

<u>To determine:</u>

The enthalpy of formation of AgCl(s)

<u>Explanation:</u>

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol


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