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Fed [463]
3 years ago
9

1) β-galactosidase is a unique enzyme, in that it can have multiple substrates. What are some other substrates for β-galactosida

se? What are some other inhibitors for β-galactosidase?
Chemistry
1 answer:
harina [27]3 years ago
4 0

The natural substrate of beta glycosidase enzyme is Ganglioside GMI, Lactosylceramide, lactose and glycoprotein.

Inhibitors of beta galactosidase enzyme is 1,4-dithiothreitol, beta marcaptoethanol, 4-chloromercurobenzoic acid and Acid-beta galactosidase.

Explanation:

Beta galactosidase enzyme performs the hydrolysis of beta galactosides into monosaccharides. It acts on aryl, amino, alkyl beta glycosidic linkages also.

The enzyme attacks on the bond formed between organic entity and galactose sugar.

It can act on multiple substrates. Some substrates are :

Ganglioside GMI

Lactosylceramide

Lactose : Enzyme beta galactosidase enzyme is a boon for lactose intolerant people because it breaks lactose in yoghurt, sour cream and cheese and makes it easy for consumption to such people.

glycoprotein : These have glycosidic bonds on which enzyme works to break the bonds.

The inhibitors for the β-galactosidase are :

  4-dithiothreitol

beta marcaptoethanol

4-chloromercurobenzoic acid

Acid-beta galactosidase.

When inhibitors are bind to enzyme it breaks down the inhibitor and reaction does not takes place.

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How many moles are 6.022(10^23) atoms of sodium
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There is only one mole
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3 years ago
If the elastic modulus of cobalt (co) is 200 gpa, and the elastic modulus of tungsten carbide (wc) is 700 gpa, calculate the upp
Dmitry_Shevchenko [17]
To determine the upper bond
Ec(u) = EmVm + EpVp
Em is the elastic modulus of cobalt.
E₁ is the elastic modulus of the particulate
Vm is the volume fraction of cobalt
Vp is the volume fraction of particulate
substitute
Ec(u) = 200 (Vm) + 700 (Vp)
To determine the lower bound
Ec (l) = EmEp/VmEp+ VpEm
Substitute
Ec (l) = 200(700)/Vm(700) + Vp (200)
Ec (l) = 1400/7Vm+2Vp
7 0
4 years ago
Which model of the atom explains the orbitals of electrons as waves
Zielflug [23.3K]

Answer:

The Bohr model of the atom explains the reactivity of all atoms.

6 0
3 years ago
Calculate the Ka for the following acid. Determine if it is a strong or weak acid.
vladimir1956 [14]

Answer:

a) Ka= 7.1 × 10⁻⁴; This is a weak acid because the acid is not completely dissociated in solution.

Explanation:

Step 1: Write the dissociation reaction for nitrous acid

HNO₂(aq) ⇄ H⁺(aq) and NO₂⁻(aq)

Step 2: Calculate the acid dissociation constant

Ka = [H⁺] × [NO₂⁻] / [HNO₂]

Ka = 0.022 × 0.022 / 0.68

Ka = 7.1 × 10⁻⁴

Step 3: Determine the strength of the acid

Since Ka is very small, nitrous acid is a weak acid, not completely dissociated in solution.

4 0
3 years ago
Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o
jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose  / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

<u>Step 4:</u> Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

<u>Step 5:</u> Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

<u>Step 6:</u> Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0
4 years ago
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