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sveta [45]
3 years ago
6

What determines how much thrust is generated in a solid fuel rocket engine at any given time?

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Answer: The amount of exposed surface area of the fuel

Explanation: APEX

Cerrena [4.2K]3 years ago
5 0

Computer drawing of a solid rocket engine with the equation

for thrust. Thrust equals the exit mass flow rate times exit velocity

plus exit pressure minus free stream pressure times nozzle area.

On this slide, we show a schematic of a solid rocket engine. Solid rocket engines are used on air-to-air and air-to-ground missiles, on model rockets, and as boosters for satellite launchers. In a solid rocket, the fuel and oxidizer are mixed together into a solid propellant which is packed into a solid cylinder. A hole through the cylinder serves as a combustion chamber. When the mixture is ignited, combustion takes place on the surface of the propellant. A flame front is generated which burns into the mixture. The combustion produces great amounts of exhaust gas at high temperature and pressure. The amount of exhaust gas that is produced depends on the area of the flame front and engine designers use a variety of hole shapes to control the change in thrust for a particular engine. The hot exhaust gas is passed through a nozzle which accelerates the flow. Thrust is then produced according to Newton's third law of motion.


The amount of thrust produced by the rocket depends on the design of the nozzle. The smallest cross-sectional area of the nozzle is called the throat of the nozzle. The hot exhaust flow is choked at the throat, which means that the Mach number is equal to 1.0 in the throat and the mass flow rate m dot is determined by the throat area. The area ratio from the throat to the exit Ae sets the exit velocity Ve and the exit pressure pe. You can explore the design and operation of a rocket nozzle with our interactive nozzle simulator program which runs on your browser.


The exit pressure is only equal to free stream pressure at some design condition. We must, therefore, use the longer version of the generalized thrust equation to describe the thrust of the system. If the free stream pressure is given by p0, the thrust F equation becomes:


F = m dot * Ve + (pe - p0) * Ae


Notice that there is no free stream mass times free stream velocity term in the thrust equation because no external air is brought on board. Since the oxidizer is mixed into the propellant, solid rockets can generate thrust in a vacuum where there is no other source of oxygen. That's why a rocket will work in space, where there is no surrounding air, and a gas turbine or propeller will not work. Turbine engines and propellers rely on the atmosphere to provide the oxygen for combustion and as the working fluid in the generation of thrust.


The thrust equation given above works for both liquid and solid rocket engines. There is also an efficiency parameter called the specific impulse which works for both types of rockets and greatly simplifies the performance analysis for rocket engines.



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Answer:

60.02 g.

Explanation:

  • It is clear from the balanced equation:

<em>Mg + 2HCl → MgCl₂ + H₂. </em>

that 1.0  mole of Mg reacts with 2.0 moles of HCl to produce 1.0 mole of MgCl₂ and 1.0 moles of H₂.

  • 20.0 g of Mg reacts with excess HCl. To calculate the no. of grams of HCl that reacted, we should calculate the no. of moles of Mg:

<em>no. of moles of Mg = mass/atomic mass</em> = (20.0 g)/(24.3 g/mol) = 0.823 mol.

  • From the balanced equation; every 1.0 mol of Mg reacts with 2 moles of HCl.

∴ 0.833 mol of Mg will react with (2 x 0.833 mol = 1.646 mol) of HCl.

<em>∴ The mass of reacted HCl = no. of moles x molar mass</em> = (1.646 mol)(36.46 g/mol) = <em>60.02 g.</em>

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3 years ago
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3 years ago
reddit The amount of NE released by sympathetic nerve terminals will be most strongly influenced by a change in which of the fol
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Answer: Extracellular [Ca2+]

Explanation:

The sensitivity and density of the alpha receptors serve to <em>enhance the response to the release of</em> <em>norepinephrine (NE)</em> . However, they do not exert a strong influence as the concentration of calcium ions on the amount of <em>norepinephrine (NE)</em> released by sympathic nerve terminals.

The release of neurotransmitters depends more on either an external or internal stimulus.This results in an action potential which on reaching a nerve terminal, results in the opening of Ca²⁺ channels in the neuronal membrane. Because the extracellular concentration of Ca²⁺ is greater than the intracellular Ca²⁺ concentration, Ca²⁺ flows into the nerve terminal. This triggers a series of events that cause the vesicles containing <em>norepinephrine (NE)</em> to fuse with the plasma membrane and release <em>norepinephrine (NE)</em> into the synapse. The higher the action potential, the higher the Ca²⁺ flow into the terminals resulting in higher amount of <em>norepinephrine (NE)</em> into the synapse, and vice versa.

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8 0
3 years ago
What is the percent ionization of a monoprotic weak acid solution that is 0.188 M? The acid-dissociation (or ionization) constan
djyliett [7]

Answer: The percent ionization of a monoprotic weak acid solution that is 0.188 M is 3.59\times 10^{-4}\%

Explanation:

Dissociation of weak acid is represented as:

HA\rightleftharpoons H^+A^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.188 M and \alpha = ?

K_a=2.43\times 10^{-12}

Putting in the values we get:

2.43\times 10^{-12}=\frac{(0.188\times \alpha)^2}{(0.188-0.188\times \alpha)}

(\alpha)=3.59\times 10^{-6}=3.59\times 10^{-4}\%

Thus percent ionization of a monoprotic weak acid solution that is 0.188 M is 3.59\times 10^{-4}\%

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