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sveta [45]
3 years ago
6

What determines how much thrust is generated in a solid fuel rocket engine at any given time?

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
8 0

Answer: The amount of exposed surface area of the fuel

Explanation: APEX

Cerrena [4.2K]3 years ago
5 0

Computer drawing of a solid rocket engine with the equation

for thrust. Thrust equals the exit mass flow rate times exit velocity

plus exit pressure minus free stream pressure times nozzle area.

On this slide, we show a schematic of a solid rocket engine. Solid rocket engines are used on air-to-air and air-to-ground missiles, on model rockets, and as boosters for satellite launchers. In a solid rocket, the fuel and oxidizer are mixed together into a solid propellant which is packed into a solid cylinder. A hole through the cylinder serves as a combustion chamber. When the mixture is ignited, combustion takes place on the surface of the propellant. A flame front is generated which burns into the mixture. The combustion produces great amounts of exhaust gas at high temperature and pressure. The amount of exhaust gas that is produced depends on the area of the flame front and engine designers use a variety of hole shapes to control the change in thrust for a particular engine. The hot exhaust gas is passed through a nozzle which accelerates the flow. Thrust is then produced according to Newton's third law of motion.


The amount of thrust produced by the rocket depends on the design of the nozzle. The smallest cross-sectional area of the nozzle is called the throat of the nozzle. The hot exhaust flow is choked at the throat, which means that the Mach number is equal to 1.0 in the throat and the mass flow rate m dot is determined by the throat area. The area ratio from the throat to the exit Ae sets the exit velocity Ve and the exit pressure pe. You can explore the design and operation of a rocket nozzle with our interactive nozzle simulator program which runs on your browser.


The exit pressure is only equal to free stream pressure at some design condition. We must, therefore, use the longer version of the generalized thrust equation to describe the thrust of the system. If the free stream pressure is given by p0, the thrust F equation becomes:


F = m dot * Ve + (pe - p0) * Ae


Notice that there is no free stream mass times free stream velocity term in the thrust equation because no external air is brought on board. Since the oxidizer is mixed into the propellant, solid rockets can generate thrust in a vacuum where there is no other source of oxygen. That's why a rocket will work in space, where there is no surrounding air, and a gas turbine or propeller will not work. Turbine engines and propellers rely on the atmosphere to provide the oxygen for combustion and as the working fluid in the generation of thrust.


The thrust equation given above works for both liquid and solid rocket engines. There is also an efficiency parameter called the specific impulse which works for both types of rockets and greatly simplifies the performance analysis for rocket engines.



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Convert a speed of 141 mi/h to units of feet per minute show work.
ozzi

Answer:

12408 feet per minute

Explanation:

Given: Speed is 141 mi/h

To find: speed in units of feet per minute

Solution:

Use the following units to convert the given speed into feet per minute.

1 mile = 5280 foot

1 h = 60 minutes

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141 mi/h =\frac{141(5280)}{60} =12408 feet per minute.

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Approx.
15
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e
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⋅
m
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−
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.
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What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.10?
IRINA_888 [86]

Answer : The concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

Solution : Given,

pH = 4.10

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Formula used : pH=-log[H_3O^+]

First we have to calculate the hydronium ion concentration by using pH formula.

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Now we have to calculate the pOH.

As we know, pH+pOH=14

4.10+pOH=14

pOH=9.9

Now we have to calculate the hydroxide ion concentration.

pOH=-log[OH^-]

9.9=-log[OH^-]

[OH^-]=antilog(-9.9)

[OH^-]=1.258\times 10^{-10}

Therefore, the concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

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