To find the volume occupied by 2.0 g of CS₂ gas we can use the ideal gas law equation
PV = nRT
where P - pressure - 726 mmHg x 133 Pa/mmHg = 96 558 Pa
V - volume
n - number of moles = mass / molar mass
number of CS₂ moles = 2.0 g / 76.15 g/mol = 0.026 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in kelvin - 70 °C + 273 = 343 K
substituting these values in the equation
96 558 Pa x V = 0.026 mol x 8.314 Jmol⁻¹K⁻¹ x 343 K
V = 0.768 L
the volume occupied is 0.768 L
Answer:
1. final pressure = 0.259atm
2. 196.84mmHg
Explanation:
Using Boyle's law of equation
P1V1 = P2V2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (mL)
V2 = final volume (mL)
According to the information given in this question:
V1 = 105mL
V2 = 352mL
P1 = 0.871atm
P2 = ?
Using P1V1 = P2V2
P2 = P1V1/V2
P2 = 0.871 × 105/352
P2 = 91.455/352
P2 = 0.2598
P2 = 0.259atm
To convert 0.259atm of the gas into mmHg, we multiply the value in atm by 760.
Hence, 0.259 × 760
= 196.84mmHg
Answer:
A person outside the bus, and a person on the bus.
Explanation:
Answer:
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Explanation:
bye answer is I don't know lol
