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2 years ago

The radius of a circle is 1 in. What is the circle's area? (Take a=3.14)

Mathematics

2 answers:

Kitty [74]2 years ago

8 0

Answer:

3.14 inches

Step-by-step explanation:

area of circle = πr²

=> 3.14 x 1 x 1

=> 3.14 inches

JulijaS [17]2 years ago

8 0

3.14 in
should be my firm answer

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Use 3.14 on all questions on this text that use pi.

alexira [117]

Answer:

$V_{cylinder}=3584\pi \thinspace yd^3$

Step-by-step explanation:

Volume of a cylinder is just the area of the circle-surface multiplied by the height of the cylinder.

$V_{cylinder}=\pi r^2 h$

We're given that the radius=8 and height=56

$V_{cylinder}=\pi r^2 h$

$V_{cylinder}=\pi (8)^2 (56)$

$V_{cylinder}=3584\pi \thinspace yd^3$

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3 years ago

A movie was 3 1/2 hours long if Lilly turned of the movie off 1/4 of the way through how much time did she spend watching

Nuetrik [128]

Answer:

7/8 of an hour

Step-by-step explanation:

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3 years ago

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Find the explicit formula for 15, 12, 9, 6,

QveST [7]

Answer:

Step-by-step explanation:

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2 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

7 0

3 years ago

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Somthing ab a mark up price, idrk tbh

gregori [183]

Since they reduced the markup price, or higher price, by 10%, the new markup price is 20% over the manufacturer price.

3 0

3 years ago