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Trava [24]
2 years ago
6

The radius of a circle is 1 in. What is the circle's area? (Take a=3.14)

Mathematics
2 answers:
Kitty [74]2 years ago
8 0

Answer:

3.14 inches

Step-by-step explanation:

area of circle = πr²

=> 3.14 x 1 x 1

=> 3.14 inches

JulijaS [17]2 years ago
8 0
3.14 in
should be my firm answer
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Use 3.14 on all questions on this text that use pi.
alexira [117]

Answer:

V_{cylinder}=3584\pi \thinspace yd^3

Step-by-step explanation:

Volume of a cylinder is just the area of the circle-surface multiplied by the height of the cylinder.

V_{cylinder}=\pi r^2 h

We're given that the radius=8 and height=56

V_{cylinder}=\pi r^2 h

V_{cylinder}=\pi (8)^2 (56)

V_{cylinder}=3584\pi \thinspace yd^3

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A movie was 3 1/2 hours long if Lilly turned of the movie off 1/4 of the way through how much time did she spend watching
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7/8 of an hour

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

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And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
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Somthing ab a mark up price, idrk tbh
gregori [183]

Since they reduced the markup price, or higher price, by 10%, the new markup price is 20% over the manufacturer price.

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