1s²2s²2p⁶3s²3p⁵
Explanation:
In writing the first two electrons will go in the 1s orbital.
Since 1s can only hold two electrons the next 2 electrons for chlorine go in the 2s orbital.
The next six electrons will go in the 2p orbital.
The p orbital can hold up to six electrons.
We'll pull six in the 2p orbital and then put the next two electrons in the 3s.
Since the 3s is now full we'll move to the 3p where we'll place the remaining five electrons.
Hope this helped ;)
1. In first reaction reactant a is the electron donor, while b is the electron acceptor,
the oxidized product is c while the reduced product is d
2. in the second equation e is the electron donor, f is the electron acceptor
g is the oxidized product while h is the reduced product.
3. In the third reaction i is the electron donor, j is the electron acceptor , k is the oxidized product while l is the reduced product.
The answer is B: friction.
A definition of friction is a resistance of an object against another, for example a tire against mud, the tire would add friction against the mud to pull away from it.
I don’t need brainliest but please just mark thanks to this answer that would help me a lot, have a nice day :)
Answer:
the reaction was that it turned green. because it used to be brown but because the rain and carbon dioxide affected it.
In the given <span>phase diagram, the line segment that describes the interface between solid and vapor is A-B. The rest of the choices do not answer teh question above</span>
