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The "dots" in a electron dot structure (Lewis Dot) represent the following:

1 answer:

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Answer : The volume of $NaOH$ required to neutralize is, 340 mL

Explanation :

To calculate the volume of base (NaOH), we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=0.300M\\V_1=85.0mL\\n_2=1\\M_2=0.150M\\V_2=?$

Putting values in above equation, we get:

$2\times 0.300M\times 85.0mL=1\times 0.150M\times V_2\\\\V_2=340mL$

Hence, the volume of $NaOH$ required to neutralize is, 340 mL

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