So let's convert this amount of mL to grams:
Then we need to convert to moles using the molar weight found on the periodic table for mercury (Hg):
Then we need to convert moles to atoms using Avogadro's number:
![\frac{6.022*10^{23}atoms}{1mole} *[8.135*10^{-2}mol]=4.90*10^{22}atoms](https://tex.z-dn.net/?f=%20%5Cfrac%7B6.022%2A10%5E%7B23%7Datoms%7D%7B1mole%7D%20%2A%5B8.135%2A10%5E%7B-2%7Dmol%5D%3D4.90%2A10%5E%7B22%7Datoms%20)
So now we know that in 1.2 mL of liquid mercury, there are 
present.
The ability to attract an electron for bonding is called (option B) Electronegativity.
This is true.
The reaction rates are affected by how often the particles collide.
Answer: There are 971.77 millimoles in 3.89 grams of Helium
Explanation:
i think its right im not really sure
A covalent bond? Not sure how much detail you want, sorry
