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EleoNora [17]
3 years ago
13

Using the Lewis dot Symbol Illustrate how the atoms are bonded in each of the following ionic compounds; thanks

Chemistry
1 answer:
Gre4nikov [31]3 years ago
6 0
I’m not really sure but i think it’s 2.
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A study is conducted to examine the effect of NaCl concentration on enzyme activity with the following results. Activity was tes
Marina86 [1]

Answer:

The answer is "Option D".

Explanation:

The behavior of 0.1M NaCl also isn't substantially larger objectively than those of 0.05M NaCl because a p-value above 0.05 (p>0.05) indicates no ability to tell differential and is a strong proof in favor of a null hypothesis.

The other wrong choices can be defined as follows:

  • Option A as it's just the reverse of the correct answer to the null.
  • Options B and C because p worth tests to support nor oppose the null hypothesis.
3 0
3 years ago
Can someone help me with the questions in the images. if they are correct i will mark as brainliest
olga nikolaevna [1]

(1)

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Chlorofluorocarbons are very harmful to the environment when released into the atmosphere. They damage the ozone layer and therefore allow more UV rays from sunlight to reach the earth’s surface. They also have a  greenhouse effect causing the earth’s atmosphere to warm up. This ultimately leads to global warming and climate change.

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Jets streams are very significant in that they influence weather patterns across the world. They are responsible for the movement of pressure systems and global air cells and their accompanying weather patterns. Because they generally sit in between cold and warm air systems they are significant in moving these air masses around. When they are weak they cause an air system to linger including storms causing excessive flooding in an area.

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6 0
4 years ago
NEED HELP ASAP NOT DIFFICULT
Burka [1]
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.

Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
5 0
3 years ago
Read 2 more answers
You are given a sulfuric acid solution of unknown concentration. You dispense 10.00 mL of the unknown solution into an Erlenmeye
dmitriy555 [2]

Answer:

"0.053457 M" of sulfuric acid.

Explanation:

The given values are:

V = 10 mL solution

V_{added} = 12.20 mL

V_{total} = 22.20 mL

then,

M 0.103 M of NaOH,

V_{rinsed} = experiment  will not be affected

V_{total \ base} = 10.38 mL

Now,

⇒  mol of NAOH = MV

                            = 0.103\times 10.38

                            =  1.06914  \ m

Whether Sulfuric acid, then

⇒  H_{2}SO_{4} + 2NaOH = Na_{2}SO_{4} + 2H_{2}O

⇒  mol \ of \ acid =\frac{1}{2}\times \ mol \   of  \ base

⇒  1.06914 \ m \ mol \ of \ base = \frac{1}{2}\times 1.06914 = 0.53457 \ m \ mol \ of \ acid

Before any dilution:

V_{sample} = 10  \ mL

⇒  M \ acid = \frac{m \ mol}{V}

                 =\frac{ 0.53457 }{10}

                 =0.053457 \ M (Sulfuric acid)

6 0
3 years ago
A student was comparing the solubility of equal amounts of table salt and table sugar at different temperatures.The table below
Mama L [17]
The sample that has the highest solubility is THE FIRST SAMPLE [TABLE SUGAR NO 1].
Solubility refers to the quantity of a solute that will dissolve in a given volume of solvent at a given temperature and pressure. The question above tells us that equal amounts of sugar and table salts were used. But looking at the table given in the question, you will see that sample 1 has the highest amount of solute that dissolve, that is 80,  the rest of the samples have values that are lower than that. 
8 0
3 years ago
Read 2 more answers
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