Answer:
Yes, this answer is correct.
Explanation:
Absolute zero is -273.15 degrees celsius
T= Tc+273.15
T is the kelvin temperature
Tc is the temperature in degrees celsius
substitute;
T= -273.15 + 273.15
T=0 K
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I. The solubility of NaCl at 25 degrees C would be between the solubilities at 20 and 30 degrees C. A reasonable answer would be 36 grams/100 g water
ii. From the table, it’s clear that the salts are more soluble at higher temperatures, indicating that an increase in temperature increases solubility.
iii. At 50 degrees C, a saturated ammonium chloride solution will have 50.6 grams of salt per 100 g water. At 20 degrees C, the solution can hold only 37.3 grams of salt per 100 g water. Thus, 13.3 grams of salt will precipitate per 100 grams of water.
Answer is b. Hope it help
Answer:
take 75 gm or it will be overdose
