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muminat
3 years ago
11

True or false? Even when soil is saturated with water, water is still available in small spaces.

Chemistry
1 answer:
kirill [66]3 years ago
8 0
This is True.........
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What do you mean by antibodies​
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Ans: a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
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Octane has a density of .692 g/mL at 20 degrees C. How many grams of O2 are required to burn 19.0 gal of C8H18?
madreJ [45]
3.64 hope that helps you 
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3 years ago
Explain what happens when two light waves traveling from the same direction of displacement meet.
Aneli [31]
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7 0
3 years ago
3.Write the symbol of the element that has a charge of +1 when it has 71 electrons.​
tigry1 [53]

The symbol : \tt _{72}^{178}Hf^{+1}

<h3>Further explanation </h3>

There are two components that accompany an element, the mass number and atomic number

Atoms are composed of 3 types of basic particles (subatomic particles): <em>protons, electrons, and neutrons </em>

The Atomic Number (Z) indicates the number of protons and electrons in an atom of an element.

Atomic number = number of protons = number of electrons ⇒ neutral number

Atomic mass is the sum of protons and neutrons

Atomic Number (Z) = Atomic mass (A) - Number of Neutrons

The element has 71 electrons and a charge of +1 , so

Number of protons = 71 + 1 = 72

Number of protons = the atomic number = 72

The element with atomic number 72 is Hafnium(Hf)

The atomic mass of Hf = 178 g/mol

4 0
3 years ago
If anyone could please help me i'd greatly appreciate it! I have tried over and over again and can not figure this out.
Papessa [141]

Answer:

%Ionization = 1.63%

Explanation:

Hydrazine in aqueous media theoretically forms a difunctional hydroxyl system. However, for this problem assume only monofunctional ionization occurs. A second hydroxyl ionization would not likely occur as the formal cationic charge formed in the 1st ionization would inhibit a second ionization.

H₂NNH₂ + 2H₂O => HONHNHOH => HONHNH⁺ + OH⁻; Kb = 1.3 x 10⁻⁶

So, assuming all OH⁻ and HONHNH⁺ are delivered in the 1st ionization then a good estimate of the %ionization can be calculated.

               HONHNHOH => HONHNH⁺  +  OH⁻

C(i) =>              0.490M                  0M           0M

ΔC =>                  -x                         +x             +x

C(eq) =>         0.490 - x                    x               x

                      ≅0.490M* => *x is dropped as Conc H₂NNH₂/Kb > 100

Kb = [HONHNH⁺][OH⁻]/[HONHNHOH]

1.3 x 10⁻⁶ = x²/0.490

=> x = [OH⁻] = [HONHNH⁺] = √[(1.3 x 10⁻⁶)(0.490)] = 8 x 10⁻⁴

=> %Ionization = (x/0.490)100% = (8 x 10⁻⁴/0.490)100% = 1.63%

7 0
3 years ago
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