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Tema [17]
3 years ago
9

Many types of scientific equipment are used to perform different functions in the science lab. Which of the following combinatio

ns of equipment would be needed to bring one liter of water to 85°C? a. Graduated cylinder, balance, beaker and hot plate b. Graduated cylinder, beaker, thermometer and hot plate c. Test tube, thermometer, and Bunsen burner d. Test tube, electronic balance and hot plate Please select the best answer from the choices provided A B C D.
Chemistry
2 answers:
scoundrel [369]3 years ago
7 0

The scientific instruments used to heat water to 85 degree Celsius has been graduated cylinder, beaker, thermometer, and hot plate. Thus, option B is correct.

Scientific equipments have been defined as the instruments and glassware that has been used in the scientific study and experimentation.

Equipments for heating the water

The water has been heated to the temperature of 85 degrees Celsius. The temperature has to be monitored thus, a thermometer has been used.

The water has been measured to be 1 L, thus the graduated cylinder, and beaker has been used for the measurement and heating of water.

The heat has been provided to the beaker by placing it on a hot plate.

Thus, the scientific instruments used to heat water to 85 degree Celsius has been graduated cylinder, beaker, thermometer, and hot plate. Thus, option B is correct.

alisha [4.7K]3 years ago
3 0

The scientific instruments used to heat water to 85 degree Celsius has been graduated cylinder, beaker, thermometer, and hot plate. Thus, option B is correct.

Scientific equipments have been defined as the instruments and glassware that has been used in the scientific study and experimentation.

<h3>Equipments for heating the water</h3>

The water has been heated to the temperature of 85 degrees Celsius. The temperature has to be monitored thus, a thermometer has been used.

The water has been measured to be 1 L, thus the graduated cylinder, and beaker has been used for the measurement and heating of water.

The heat has been provided to the beaker by placing it on a hot plate.

Thus, the scientific instruments used to heat water to 85 degree Celsius has been graduated cylinder, beaker, thermometer, and hot plate. Thus, option B is correct.

Learn more about scientific equipments, here:

brainly.com/question/24690874

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In a chemical equation coefficients indicate the number of molecules/atoms involved in the reaction.
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Olympic cyclists fill their tires with helium to make them lighter. Assume that the volume of the tire is 860 mL , that it is fi
nata0808 [166]

Answer:

a)  the mass of air = 8.24 grams

b) the mass of helium = 1.14 grams

c) the mass difference = 7.10 grams

Explanation:

Step 1: Data given

Volume of the tire = 860 mL

Total pressure = 120 psi

Temperature = 26°C

molar mass of air = 28.8 g/mol

Step 2:  Convert psi to atm

(

120 psi) (1 atm / 14.7 psi) = 8.163

Step 4: Calculate moles

PV = nRT

 ⇒ with P = the pressure = 8.163 atm

⇒ with V = the volume = 860 mL = 0.860 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the universal gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 26 °C = 299 Kelvin

n = (8163*0.860)/(0.08206*299)

n = 0.2861 moles of gas

Step 5: Calculate the mass of air in an air-filled tire.

Mass = moles * molar mass

Mass = (0.2861 moles of gas) (28.8 g/mol)  

Mass = 8.24 grams

Step 6: Calculate the mass of helium in a helium- filled tire.

mass of helium = 0.2861 moles of gas * 4 g/mol)  

mass of helium  = 1.14 grams

Step 7: What is the mass difference between the two?

Δmass=  8.24 grams -  1.14 grams

Δmass= 7.10 grams

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4 years ago
Why does liquids rate of evaporation increase when the liquid is heated
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Boiling liquids that want to escape gas
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A mixture with H2 and He exerts a total pressure of 0.48 atm. If there is 1.0 g of H2 and 1.0 g of He in the mixture, what is th
lara [203]

Answer is: the partial pressure of the helium gas is 0.158 atm.

p(mixture) = 0.48 atm; total pressure.

m(H₂) = 1.0 g; mass of hydrogen gas.

n(H₂) = m(H₂) ÷ M(H₂).

n(H₂) = 1.0 g ÷ 2 g/mol.

n(H₂) = 0.5 mol; amount of hydrogen.

m(He) = 1.0 g; mass of helium.

n(He) = 1 g ÷ 4 g/mol.

n(He) = 0.25 mol; amount of helium.

χ(H₂) = 0.5 mol ÷ 0.75 mol.

χ(H₂) = 0.67; mole fraction of hydrogen.

χ(He) = 0.25 mol ÷ 0.75 mol.

χ(He) = 0.33; mole fraction of helium.

p(He) = 0.33 · 0.48 atm.

p(He) = 0.158 atm; the partial pressure of the helium gas.

8 0
3 years ago
Given the data you collected for the volume of water displaced by 25.000 g of aluminum, what is the density of aluminum?
vovikov84 [41]

Answer:

C. 2.70 g/mL

Explanation:

Density is the ratio between the mass of a substance and the volume it occupies. Based on Archimedes' volume, the displaced volume of the aluminium is the volume it occupies. To solve this question we must find the difference in volume between initial volume of water = 30mL and final volume of water + aluminium = 39.26mL. This difference is the volume of the aluminium. With its mass we can find density:

39.26mL - 30mL = 9.26mL

Density = 25.00g / 9.26mL =

2.70g/mL

Right answer is:

<h3>C. 2.70 g/mL </h3>

6 0
3 years ago
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