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Andrei [34K]
3 years ago
10

A piston has an initial volume of 1.643 L at a pressure of 128 kPa. The temperature is maintained at 27 oC as the volume is decr

eased to 0.593 L. What is the new pressure in kilopascals?
Chemistry
1 answer:
aivan3 [116]3 years ago
8 0

Answer:

  • <u>355 kPa</u>

Explanation:

The ideal gases follow Boyle's law: at constant temperature pressure and volume are inversely related:

       PV=constant

       P_1V_1=P_2V_2

       P_2=\dfrac{P_1V_1}{V_2}

Subsituting and computing:

     P_2=\dfrac{1.643L\times 128kPa}{0.593L}\approx355kPa

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a carbohydrate is called an organic compound because it contains a) phosphorus b) carbon c) hydrogen d) oxygen
artcher [175]
Organic chemistry is all about CARBON!!!!!!
3 0
3 years ago
A multivitamin tablet contains 40 milligrams of potassium. how many moles of potassium does each tablet contain?
katrin2010 [14]
Conversion of mole to grams
k in mole = 1 mole/ atomic mass
K in mole =1/ 39.0983 g/mole
                = 0.255765 g/mole
converting 40 grams of K
 K 40 grams x [ 1 mole/ 39.0983 grams] = 1.0230623 mole
There are 1.0230623 moles of K in 40 K of Potassium

7 0
3 years ago
Read 2 more answers
It is found that a gas undergoes a first-order decomposition reaction. If the rate constant for this reaction is 8.1 x 10-2 /min
kap26 [50]

Answer:

28.43 min

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 8.1\times 10^{-2} min⁻¹

Initial concentration [A_0] = 0.1 M

Final concentration [A_t] = 1.0\times 10^{-2} M

Time = ?

Applying in the above equation, we get that:-

1.0\times 10^{-2}=0.1e^{-8.1\times 10^{-2}\times t}

0.1e^{-8.1\times \:10^{-2}t}=10^{-2}

e^{-8.1\times \:10^{-2}t}=\frac{1}{10}

\ln \left(e^{-8.1\times \:10^{-2}t}\right)=\ln \left(\frac{1}{10}\right)

t=28.43\ min

3 0
3 years ago
What is the atomicity of carbon monoxide
Scilla [17]

I believe the answer is two

7 0
3 years ago
What is the molarity (M) of .5 liter of a solution that has 205 g of NaCl dissolved in it?
jeka94

Answer:

<h2>Molarity = 7 mol / L</h2>

Explanation:

Since the mass of NaCl and it's volume has been given we can find the molarity by using the formula

<h3>C =  \frac{m}{M \times v}</h3>

where

C is the molarity

m is the mass

M is the molar mass

v is the volume

From the question

v = 0.5 L

m = 205 g

We must first find the molar mass and then substitute the values into the above formula

M( Na) = 23 , M( Cl) = 35.5

Molar mass of NaCl = 23 + 35.5 =

58.5 g/mol

So the molarity of NaCl is

C =  \frac{205}{0.5  \times 58.5}  \\ C =  \frac{205}{29.25}

C = 7.00854

We have the final answer as

<h3>Molarity = 7 mol / L</h3>

Hope this helps you

8 0
3 years ago
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