Question

A piston has an initial volume of 1.643 L at a pressure of 128 kPa. The temperature is maintained at 27 oC as the volume is decreased to 0.593 L. What is the new pressure in kilopascals?

Answer 1

Answer:

• 355 kPa

Explanation:

The ideal gases follow Boyle's law: at constant temperature pressure and volume are inversely related:

       $PV=constant$

       $P_1V_1=P_2V_2$

       $P_2=\dfrac{P_1V_1}{V_2}$

Subsituting and computing:

     $P_2=\dfrac{1.643L\times 128kPa}{0.593L}\approx355kPa$