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Andrei [34K]
3 years ago
10

A piston has an initial volume of 1.643 L at a pressure of 128 kPa. The temperature is maintained at 27 oC as the volume is decr

eased to 0.593 L. What is the new pressure in kilopascals?
Chemistry
1 answer:
aivan3 [116]3 years ago
8 0

Answer:

  • <u>355 kPa</u>

Explanation:

The ideal gases follow Boyle's law: at constant temperature pressure and volume are inversely related:

       PV=constant

       P_1V_1=P_2V_2

       P_2=\dfrac{P_1V_1}{V_2}

Subsituting and computing:

     P_2=\dfrac{1.643L\times 128kPa}{0.593L}\approx355kPa

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4 0
3 years ago
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Answer:

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4 0
3 years ago
URGENT!!-- Please help!
blondinia [14]

Moles of gas = 0.369

<h3>Further explanation</h3>

Given

P = 2 atm

V = 5.3 L

T = 350 L

Required

moles of gas

Solution

Ideal gas Law

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{2\times 5.3}{0.082\times 350}\\\\n=0.369

Avogadro's law : at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

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3 0
2 years ago
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8 0
3 years ago
Read 2 more answers
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