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Tasya [4]
4 years ago
12

Why does the flask have to be closed during the water and alka seltzer reaction?

Chemistry
1 answer:
Grace [21]4 years ago
6 0
This is to prevent the gas from escaping!
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Given the chemical equation: KI +Pb(NO3)2—>KNO3 + Pbl2
Andrew [12]

Answer:

2KI +Pb(NO_3)_2\rightarrow 2KNO_3 + Pbl_2

Double replacement reaction.

It is in agreement with the law of conservation of mass because we have two potassium atoms, two iodine atoms, one lead atom, two nitrogen atoms and six oxygen atoms on both sides of the chemical equation (count them).

Explanation:

Hello there!

In this case, according to the given information, it turns possible for us to solve this problem by firstly considering that this reaction occurs between potassium iodide and lead (II) nitrate to yield potassium nitrate and lead (II) iodide which is clearly not balanced since we have one iodine atom on the reactants and two on the products, that is why the balance implies the placement of a coefficient of 2 in front of both KI and KNO3 as shown below:

2KI +Pb(NO_3)_2\rightarrow 2KNO_3 + Pbl_2

Thus, we infer this is a double replacement reaction due to the exchange of both cations, K and Pb with both anions, I and NO3. Moreover, we can tell this balanced reaction is in agreement with the law of conservation of mass because we have two potassium atoms, two iodine atoms, one lead atom, two nitrogen atoms and six oxygen atoms on both sides of the chemical equation (count them).

Regards!

7 0
4 years ago
A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.60 atm. What is the partial pressure of Ar
DaniilM [7]
The partial pressure of Ne is 1.06 atm. The answer is a. 1.1 atm

8 0
3 years ago
Read 2 more answers
What is the excess reactant in the combustion of 23 g of methane in the open atmosphere?
Marta_Voda [28]

Answer : The excess reactant in the combustion of methane in opem atmosphere is O_{2} molecule.

Solution : Given,

Mass of methane = 23 g

Molar mass of methane = 16.04 g/mole

The Net balanced chemical reaction for combustion of methane is,

CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(g)

First we have to calculate the moles of methane.

\text{ Moles of methane}=\frac{\text{ Given mass of methane}}{\text{ Molar mass of methane}} = \frac{23g}{16.04g/mole} = 1.434 moles

From the above chemical reaction, we conclude that

1 mole of methane react with the 2 moles of oxygen

and 1.434 moles of methane react to give \frac{2moles\times 1.434moles}{1moles} moles of oxygen

The Moles of oxygen = 2.868 moles

Now we conclude that the moles of oxygen are more than the moles of methane.

Therefore, the excess reactant in the combustion of methane in open atmosphere is O_{2} molecule.


6 0
3 years ago
Help plz I will give brain
mel-nik [20]

it wont let me enter answer

3 0
3 years ago
What are the three key things in science?
stiv31 [10]

Answer:

The three key things in Science are:

Physical Science,Earth Science and Life Science

If the answer helps you PLEASE mark me as brainliest

Stay Safe,Stay Healthy and Stay Happy

5 0
3 years ago
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