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azamat
2 years ago
6

Which value from the set {4,6,8,10} will make p+p+p+p=24 true?A.4B.6C.8D.10​

Mathematics
1 answer:
muminat2 years ago
6 0

Answer:

I think B.6 is the answer

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GreenBeam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a m
Harrizon [31]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 3.50 mg  

     Alternate Hypothesis, H_A : \mu > 3.50 mg

(b) The value of z test statistics is 2.50.

(c) We conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

(d) The p-value is 0.0062.

Step-by-step explanation:

We are given that Green Beam Ltd. claims that its compact fluorescent bulbs average no more than 3.50 mg of mercury. A sample of 25 bulbs shows a mean of 3.59 mg of mercury. Assuming a known standard deviation of 0.18 mg.

<u><em /></u>

<u><em>Let </em></u>\mu<u><em> = average mg of mercury in compact fluorescent bulbs.</em></u>

So, Null Hypothesis, H_0 : \mu \leq 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is no more than 3.50 mg}

Alternate Hypothesis, H_A : \mu > 3.50 mg     {means that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg}

The test statistics that would be used here <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                          T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean mg of mercury = 3.59

            \sigma = population standard deviation = 0.18 mg

            n = sample of bulbs = 25

So, <em><u>test statistics</u></em>  =  \frac{3.59-3.50}{\frac{0.18}{\sqrt{25} } }

                               =  2.50

The value of z test statistics is 2.50.

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 2.50) = 1 - P(Z \leq 2.50)

                                             = 1 - 0.9938 = 0.0062

<em />

<em>Now, at 0.01 significance level the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the average mg of mercury in compact fluorescent bulbs is more than 3.50 mg.

6 0
3 years ago
Determine a series of transformations that would map Figure E onto Figure F.
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Answer:

Step-by-step explanation:

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3 years ago
what are the first 5 common multiples of 14 and 20? i’ll mark brainliest for whoever answers first!!!
shutvik [7]

Answer:

14, 28, 42, 56, and 70 are the first 5 common multiples of 14

20, 40, 60, 80, and 100 are the first 4 common multiples of 20

8 0
3 years ago
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1. Classify each statement as true or false for all real numbers a, b,<br> and c.
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naw

g4jtnbjtrnjbnrtibnrijnbngtrjnb jtkgnbrbgbn

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3 years ago
F(1)=2, f(n)= f(n-1)+7 <br><br> Plsss help
grigory [225]

Answer:

6

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2

3

1

4

5

6

7

8

9

10

11

12

13

15

16

17

18

19

20

7 0
2 years ago
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