Question

On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (negative 6, negative 5) and (0, 0). Line J K goes through (negative 6, 1) and (0, negative 4). Line P Q goes through (negative 5, 4) and (0, negative 2).
Which line is perpendicular to a line that has a slope of Negative five-sixths?

Answer 1

Answer:

The slope of line LM is perpendicular to the given line.

Step-by-step explanation:

L (- 5, - 3), M (0, 3)

N (- 6, - 5) , O (0, 0)

J (- 6, 1) , K (0, - 4)

Slope of given line = -5/6

Slope of perpendicular line = 6/5

Slope of line LM

$\frac{3 + 3}{0 + 5}=\frac{6}{5}$

Slope of line NO

$\frac{0+5}{0+6}=\frac{5}{6}$

Slope of line JK

$\frac{-4-1}{0+6}=\frac{-5}{6}$