Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.
Explanation:
Given: n = 2
The relation between energy and
orbit of an atom is as follows.
![E = - \frac{13.6}{n^{2}} eV](https://tex.z-dn.net/?f=E%20%3D%20-%20%5Cfrac%7B13.6%7D%7Bn%5E%7B2%7D%7D%20eV)
Substitute the values into above formula as follows.
![E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV](https://tex.z-dn.net/?f=E%20%3D%20-%20%5Cfrac%7B13.6%7D%7Bn%5E%7B2%7D%7D%20eV%5C%5C%3D%20-%20%5Cfrac%7B13.6%7D%7B%282%29%5E%7B2%7D%7D%5C%5C%3D%20-%203.40%20eV)
The negative sign indicates that energy is being released.
Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.
HCL + NaOH —> H2O + NaCl
It’s a double replacement reaction