Answer:
15.06 × 10²³ atoms of Li
Explanation:
Given data:
Number of moles of Li = 2.5 mol
Number of toms of Li = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen
For 2.5 mol of Li:
1 mole of lithium = 6.022 × 10²³ atoms of Li
2.5 mol × 6.022 × 10²³ atoms of Li / 1 mol
15.06 × 10²³ atoms of Li
While metal B is being reduced from an ion to a solid metal, metal A is being oxidized.
Metal A is being displaced because, through oxidation, it transforms from a solid metal to ions in a solution.
What is Oxidation ?
Redox reactions include a change in the oxidation state of the substrate. Loss of electrons or a rise in an element's oxidation state are both considered to be oxidation.
Gaining electrons or lowering the oxidation state of an element or its constituent atoms are both examples of reduction.
In general, the term "reduction" refers to a reaction in which a chemical receives additional electrons; the compound that gets electrons is referred to as being reduced. We can think of the transformation of a ketone or an aldehyde into an alcohol as a two-electron reduction because hydride can be thought of as a proton plus two electrons.
So finally we can say that Metal A is being oxidized.
To know more about Oxidation please click here : brainly.com/question/25886015
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Answer: 10 cm3
Explanation:
Mass of sample of steel (m) = 80 grams
density of sample of steel (p) = 8 g/cm3 samples volume (v) = ?
Since density is obtained by dividing mass by volume, the density of the steel sample is expressed as:
density = mass / volume
p = m / v
make v the subject formula
v = m / p
v = 80 grams / 8 g/cm3
v = 10 cm3
Thus, the samples volume is 10 cm3
