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Kaylis [27]
3 years ago
7

Which of the following the scenarios represent an exponential relationship?

Mathematics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

A) A car with an initial value of $32,000 is depreciating in value at a rate of 8.5% each year

(B) A job pays a base salary of 12,000 and increases annually at a rate of 7%

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for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation
Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                             P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample proportion of defective items = 12,898

             s = sample standard deviation = 7,719

            n = sample size = 5

             \mu = population mean

<em> Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation. </em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ; </u>

P(-2.776 < t_4 < 2.776) = 0.95  {As the critical value of t at 4 degrees of

                                               freedom are -2.776 & 2.776 with P = 2.5%}  

P(-2.776 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.776) = 0.95

P( -2.776 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.776 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.776 \times {\frac{s}{\sqrt{n} } } , \bar X+2.776 \times {\frac{s}{\sqrt{n} } } ]

                                = [ 12,898-2.776 \times {\frac{7,719}{\sqrt{5} } } , 12,898+2.776 \times {\frac{7,719}{\sqrt{5} } } ]

                               = [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0
4 years ago
The astrolabe, an example of improved technology of the 15th and 16th centuries, had the GREATEST impact on
Crank
I believe the correct answer from the choices listed above is option C. <span>The astrolabe, an example of improved technology of the 15th and 16th centuries, had the greatest impact on the navigation skills. Hope this answers the question. Have a nice day.</span>
7 0
4 years ago
Read 2 more answers
Find the length of the line joining the points A(-2,10) and B(-8,2)
Vesnalui [34]

Length of the line

= \sqrt{((-2)-(-8))^{2}+(10-2)^{2}  }

= \sqrt{36+64}

=\sqrt{100}

= 10

6 0
2 years ago
Help me with this! Choose 3 please!!
Vlad [161]
F(3) = 18...true
f(-3) = 6...true
f(-22) = -56...false
f(-12) = -12...true
f(-1) = 11...false

4 0
4 years ago
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Use the quadratic formula to find the solution to the question <br> 3x^2-10x+5=0
nlexa [21]

Answer:

x_{1}  = \frac{5 + \sqrt{10} }{3}  and x_{2} = \frac{5 - \sqrt{10} }{3}

Step-by-step explanation:

3x^2-10x+5=0

x_{1} = \frac{10 + \sqrt{10^{2}-4*3*5 } }{2*3}                  x_{2} = \frac{10 - \sqrt{10^{2}-4*3*5 } }{2*3}

x_{1} = \frac{10 + \sqrt{100-60} }{6}                      x_{2} = \frac{10 - \sqrt{100-60} }{6}

x_{1} = \frac{10 + \sqrt{40} }{6}                            x_{2} = \frac{10 - \sqrt{40} }{6}

x_{1} = \frac{10 + 2\sqrt{10} }{6}  / 2                    x_{2} = \frac{10 - 2\sqrt{10} }{6}  / 2

x_{1}  = \frac{5 + \sqrt{10} }{3}                             x_{2} = \frac{5 - \sqrt{10} }{3}

3 0
3 years ago
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