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3 years ago

Solve linear equations Solve for x -2(4x + 3) = 3(x + 1)

Mathematics

2 answers:

inna [77]3 years ago

7 0

Answer:

x = - $\frac{9}{11}$

Step-by-step explanation:

Given

- 2(4x + 3) = 3(x + 1) ← distribute parenthesis on both sides

- 8x - 6 = 3x + 3 ( subtract 3x from both sides )

- 11x - 6 = 3 ( add 6 to both sides )

- 11x = 9 ( divide both sides by - 11 )

x = - $\frac{9}{11}$

Mice21 [21]3 years ago

6 0

Answer: X = - 9/11

Step on step equations :

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Multiplying an even number of negative numbers gives an answer that is ______________ choose from:positive

fomenos

Keywords:

Pair of numbers, negatives, law of signs, multiply

For this case we must say that it is obtained by multiplying any even number of negative numbers, that is, if a positive or negative number is obtained.

We must bear in mind that the Law of Signs states that:

$+ * + = +\\+ * - = -\\- * + = -\\- * - = +$

For example:

Let -a, -b, -c, -d negative numbers, we have:

A pair: $(-a) * (- b) = + ab$

Two pairs: $(-a) * (- b) * (- c) * (- d) = (+ ab) * (+ cd) = + abcd$

This is true for the multiplication of any pair of negative numbers.

So, the answer is: You get a positive number

Answer:

A positive number is obtained

4 0

4 years ago

The distance traveled by a toy car can be modeled by D(t) = t3 − 3t2 + t − 3, where t > 3 represents time in seconds. If the

Bogdan [553]

Answer:

$t^2+1$

Step-by-step explanation:

We are given that

Distance traveled by a toy car

$D(t)=t^3-3t^2+t-3$

Where t>3

Time taken by car =t-3 seconds

We have to find the expression which represents the speed of the toy car.

We know that

$Speed=\frac{Distance}{time}$

Using the formula

$Speed=\frac{(t^3-3t^2+t-3)}{t-3}$

$Speed=\frac{t^2(t-3)+(t-3)}{t-3}$

$Speed=\frac{(t-3)(t^2+1)}{t-3}$

$Speed=t^2+1$

Hence, the expression which represents the speed of the toy car

$t^2+1$

5 0

3 years ago

Guys I need your help, help me with this question please

mario62 [17]

Answer:

actually I am sorry I dont rly know but I need some points

Step-by-step explanation:

7 0

3 years ago

The measure of an angle formed by two secants intersecting outside the circle equals

sineoko [7]

When two secants (Line A + B and Line C + D) intersect, they form an angle (∠y) equal to:
½ (the larger intercepted arc minus the smaller intercepted arc)

(Make sure to look at the graphic I posted)