2,205 hours a year.
245 days a year.
-9 is a negative number, so plus 25, it would be 16. The minus sign and the negative sign of -10 cancel out, so it is plus 10, ending up with 26. Finally, the + and - becomes negative (positive times negative equals negative), so it is -6 and you’ll end up with a final answer of 20.
Answer:g(−219.6g+45.6)
Step-by-step explanation:
−6g+9g(0.6)(g+9)−g(6−9)−g(6+9)g(6+9)
−219.6g2+45.6g
=g(−219.6g+45.6)
Answer:
Therefore,
The length of the path traced by the outer tip of the minute hand in one hour, is 88 inches.
Step-by-step explanation:
Given:
The length of the minute hand of a clock is,
Which is as Radius,
Therefore,
Radius = r = length of the minute hand = 14\ inches
pi = 22/7
To Find:
The length of the path traced by the outer tip of the minute hand in one hour, will be One full rotation, that is
Circumference, C = ?
Solution:
Circumference, is given by,
Therefore,
The length of the path traced by the outer tip of the minute hand in one hour, is 88 inches.
Explanation:
There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.
<u>Statement</u> . . . . <u>Reason</u>
2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle
3. AD ≅ BD
and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle
4. ∠CAE = ∠CAD +∠DAE
and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate
5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality
6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality
7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality
8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate
9. ∠ACD ≅ ∠BCD . . . . CPCTC
10. DC bisects ∠ACB . . . . definition of angle bisector
