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Sav [38]
3 years ago
8

Need help on this please

Physics
1 answer:
marin [14]3 years ago
3 0
The answer is D, the amount of energy stays the same.
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A 1000-kg car is traveling east at 20\:m.s^{-1}20 m . s − 1 and a 1200-kg car is traveling west at 22\:m.s^{-1}\:22 m . s − 1. W
nydimaria [60]

Answer:

490,400 J

Explanation:

Mass of first car, m = 1000 kg

Mass of second car, M = 1200 kg

velocity of first car, u = 20 m/s east

velocity of second car, U = 22 m/s west

The formula for the kinetic energy is

k = \frac{1}{2}mv^{2}

where, m is the body and v be the velocity of the body.

Total kinetic energy is given by

k = \frac{1}{2}mu^{2}+\frac{1}{2}MU^{2}

k = \frac{1}{2}\times1000\times20^{2}+\frac{1}{2}\times1200\times22^{2}

k = 200000 + 290400

k = 490,400 J

Thus, the total kinetic energy of the system is 490,400 J.

3 0
3 years ago
Daffy Duck is standing 6.8 m away from Minnie Duck. The attractive gravitational force between them is 5.4x10-8 N. If Daffy Duck
artcher [175]

Answer:

432.78 Kg

Explanation:

From the question given above, the following data were obtained:

Distance apart (r) = 6.8 m

Force of attraction (F) = 5.4×10¯⁸ N

Mass of Daffy Duck (M₁) = 86.5 kg

Mass of Minnie Duck (M₂) =?

NOTE: Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

The mass of Minnie Duck can be obtained as follow:

F = GM₁M₂ / r²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 6.8²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 46.24

Cross multiply

6.67×10¯¹¹ × 86.5 × M₂ =5.4×10¯⁸ × 46.24

Divide both side by 6.67×10¯¹¹ × 86.5

M₂ = 5.4×10¯⁸ × 46.24 / 6.67×10¯¹¹ × 86.5

M₂ = 432.78 Kg

Therefore, the mass of Minnie Duck is 432.78 Kg

8 0
3 years ago
Convert 325 cm to yards I need the answer ASAP
Ira Lisetskai [31]
325 /91 = 3.571 yards
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3 years ago
Can someone explain to me what potential difference is? Simple answers are always better! P.s : Last time my electricity questio
Artyom0805 [142]
<span>the difference of electrical potential between two points. hope this helps</span>
3 0
3 years ago
Which type of circuit is becoming more common in residential electrical design and construction?
jekas [21]

Communication circuit  <em>(D)</em> is becoming more common in residential electrical design and construction.  

LAN Ethernet cables, outlets, and even hubs and bridges, are being built into the walls of new homes, along with the usual electrical outlet wiring, to give the owner the networking infrastructure and internet access that everybody needs now ... without stringing a mess of cables on the floor and through doors all over the house.

3 0
3 years ago
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