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2 years ago

In which direction does the electric field point at a position directly east of a

Physics

1 answer:

svlad2 [7]2 years ago

3 0

Answer:

<h2>D. East </h2><h3>That's my correct answer</h3>

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A runner begins running at the beginning of 7th period and stops running at the end of the period. She runs at a pace of 10 km/h

MrRissso [65]

Answer:

She run for, t = 0.92 s

Explanation:

Given data,

The velocity of the runner, v = 10 km/h

The distance covered by the runner, d = 9.2 km

The relationship between the velocity, displacement and time is given by the formula,

t = d / v

Substituting the given values in the above equation,

t = 9.2 / 10

= 0.92 s

Hence, she ran for, t = 0.92 s

8 0

2 years ago

A tube with a cap on one end, but open at the other end, has a fundamental frequency of 130.8 Hz. The speed of sound is 343 m/s

sergey [27]

Answer:

Y = V / f where Y equals wavelength

4 Y1 = V / f1 for a closed pipe the wavelength is 1/4 the length of the pipe

2 Y2 = V / f2 for the open pipe the wavelength is 1/2 the length of the pipe

Y1 / Y2 = 2 = f2 / f1 dividing equations

f2 = 2 f1

the new fundamental frequency is 2 * 130.8 = 261.6

(The new wavelength is 1/2 the original wavelength so the frequency must double to produce the same speed.

8 0

2 years ago

Two bodies made of the same material have same external dimension and appearance, but one is compact solid and other is hollow.

Bumek [7]

Answer:

Different

Explanation:

The hollow one will expand even more making it have a larger volume then the solid one so they are different

5 0

2 years ago

Along the line connecting the two charges, at what distance from the charge q1 is the total electric field from the two charges

Nostrana [21]

Answer:

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

Explanation:

Here two charges are placed at distance "d" apart

now the net value of electric field at some position between two charges will be ZERO

so we will have

electric field due to charge 1 = electric field due to charge 2

$E_1 = E_2$

Let the position where net field is zero will lie at distance "r" from q1

$\frac{kq_1}{r^2} = \frac{kq_2}{(d-r)^2}$

now we will have

$\frac{(d - r)^2}{r^2} = \frac{q_2}{q_1}$

now square root both sides

$\frac{d}{r} - 1 = \sqrt{\frac{q_2}{q_1}}$

now we have

$\frac{d}{r} = \sqrt{\frac{q_2}{q_1}} + 1$

so we have

$r = d (\frac{\sqrt {q_1}}{\sqrt{q_1} + \sqrt{q_2}})$

8 0

2 years ago

Which of the following explains how an executive order differs from a law?

Novay_Z [31]

Answer:

Executive Orders state mandatory requirements for the Executive Branch, and have the effect of law. They are issued in relation to a law passed by Congress or based on powers granted to the President in the Constitution and must be consistent with those authorities.

Explanation:

3 0

2 years ago