Answer: (A) SAS (B) No (C) SSS (D) No
<u>Step-by-step explanation:</u>
A) ET ≅ MT, ∠T ≅ ∠T, TA ≅ TA ⇒ Side-Angle-Side
B) top and base are congruent, diagonal is congruent to itself, but there is no way to prove that two angles are congruent without knowing if either of the sides are parallel.
C) JU ≅ JE, UN ≅ EN, JN ≅ JN ⇒ Side-Side-Side
D) angle-angle-angle only proves similarity, not congruency
-3(6-10v-5v)
=-3(6-15v)
=-18+45v
-18+45v is the final answer.
Yes your answers look correct nice job
Answer:
the dimensions of the box that minimizes the cost are 5 in x 40 in x 40 in
Step-by-step explanation:
since the box has a volume V
V= x*y*z = b=8000 in³
since y=z (square face)
V= x*y² = b=8000 in³
and the cost function is
cost = cost of the square faces * area of square faces + cost of top and bottom * top and bottom areas + cost of the rectangular sides * area of the rectangular sides
C = a* 2*y² + a* 2*x*y + 15*a* 2*x*y = 2*a* y² + 32*a*x*y
to find the optimum we can use Lagrange multipliers , then we have 3 simultaneous equations:
x*y*z = b
Cx - λ*Vx = 0 → 32*a*y - λ*y² = 0 → y*( 32*a-λ*y) = 0 → y=32*a/λ
Cy - λ*Vy = 0 → (4*a*y + 32*a*x) - λ*2*x*y = 0
4*a*32/λ + 32*a*x - λ*2*x*32*a/λ = 0
128*a² /λ + 32*a*x - 64*a*x = 0
32*a*x = 128*a² /λ
x = 4*a/λ
x*y² = b
4*a/λ * (32*a/λ)² = b
(a/λ)³ *4096 = 8000 m³
(a/λ) = ∛ ( 8000 m³/4096 ) = 5/4 in
then
x = 4*a/λ = 4*5/4 in = 5 in
y=32*a/λ = 32*5/4 in = 40 in
then the box has dimensions 5 in x 40 in x 40 in
