Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
So that would be the same thing as 5 4/5 - 3 2/7
Put them in mixed fractions to become 29/5 - 23/7
Multiply one side by 7 and one side by 5 to get the same denominator
203/35 - 115/35
Now subtract the numerators to get
88/35
Or if they want it inixed numbers then 2 18/35
Given 12−(−2) over a line 12−6÷2
We can use PEMDAS rule and solve the expression in the order as given below:-
1. Parentheses
2. Exponents
3. Multiplication
4. Division
5. Addition
6. Subtraction
Now solving for given expression:-
So final answer is 14/9 i.e. 14 over 9.
3n<50
n<50/3
The variable N represents a whole number.
For what values of n will the sum of n+3 be less than 50?
Answer:
n = 13
Step-by-step explanation:
20= -6+2n
Add 6 to each side
20+6= -6+6+2n
26 = 2n
Divide each side by 2
26/2 = 2n/2
13 =n
