Answer:
it is not D!! i took the test and it was wrong on plato
Explanation:
B. 1, 2, 1, 2. You balance the equation by making sure there are equal elements on both sides.
Answer:
I believe it would be a solution I could be wrong tho
Explanation:
a.
Ionic bond is a bond in which there is complete transfer of valence electrons between atoms.
The atom that loses the valence electron is called the electron donor while the atom that accepts the electron is called the electron acceptor.
Ionic bond usually occurs between metals and non metals.
Ionic bond is a bond in which there is complete transfer of valence electrons between atoms.
b.
The force of attraction between Na⁺ and Cl⁻ forms the ionic bond.
- In the formation of NaCl, Na has one valence electron in its outermost shell and Cl needs one electron to complete the stable octet configuration.
- Na donates its valence electron to Cl to form the ionic bond. So, the Na atom becomes positively charged with a charge of +1 while the Cl atom becomes negatively charged with a charge of -1.
Since the atoms are now charged, the force of attraction between them forms the ionic bond.
c.
The force of attraction between Mg²⁺ and O²⁻ forms the ionic bond.
- In the formation of MgO, Mg has two valence electrons in its outermost shell and O needs two electrons to complete the stable octet configuration.
- Mg donates its two valence electron to O to form the ionic bond. So, the Mg atom becomes positively charged with a charge of +2 while the O atom becomes negatively charged with a charge of -2.
Since the atoms are now charged, the force of attraction between them forms the ionic bond.
Learn more about ionic bond here:
brainly.com/question/13526463
2.1653 g
Explanation:
The molar mass of Rubidium is;
85.468 g/mol
Therefore the moles of Rubidium that reacted with oxygen is;
1.98 / 85.468
= 0.0232 moles
If every two moles of Rubidium reacts with one mole of oxygen then the amount of oxygen consumed in the chemical reaction is;
0.5 * 0.0232
= 0.0116 moles
The molar mass of an oxygen atom is 16 g/mole. Then the amount of O in grams consumed is;
0.0116 * 16
=0.1853 g
The final weight of the Rubidium II Oxide is;
1.98 + 0.1853
= 2.1653 g
