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german
3 years ago
5

Please help me thanks so much....I’ll mark you?!?!:)))) ( 15 points)

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
7 0

Answer:

all of the above

Explanation:

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How many grams of a 23.4% by mass naf solution is needed if you want to have 1.33 moles of naf?
jenyasd209 [6]
Percentage by mass is the mass of NaF present in 100 g of the solution.
the percentage by mass of NaF is 23.4 %
this means that in 100 g of solution, mass of NaF present is 23.4 g
the number of moles of NaF present - 1.33 mol
mass of NaF - 1.33 mol x 42 g/mol = 55.9 g
when there's 23.4 g of NaF - mass of solution is 100 g
therefore when there's 55.9 g of NaF - mass of solution is 100 / 23.4 x 55.9 
= 239 g
mass of solution required is 239 g
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Answer:

Explanation:

Kindly note that I have attached the complete question as an attachment.

Here, we are told that elimination occurs by an E2 mechanism. What this means is that the hydrogen and the halogen must be above and below for the reaction to proceed.

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Please check attachment for complete equations and diagrams of compounds too.

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What mass of KNO, will dissolve in 100 g of water at 100°C?
Sphinxa [80]

Answer:

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Explanation:

Hello!

In this case, according to the reported solubility data for potassium nitrate at different temperatures on the attached picture, it is possible to bear out that about 170-180 grams of potassium nitrate are completely dissolved in 100 g; considering that the solubility is the maximum amount of a solute that can be dissolved in a solvent, in this case water.

Best regards!

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