This problem is asking for the consumption of silver ions when silver nitrate is reacted with copper. In such a case, since no masses are given, we can use the following from similar problems:
Mass of empty beaker: 110.000 g
Mass of beaker with silver nitrate (after all additions) and copper: 331.634 g.
Mass of beaker with silver: 113.395 g.
This means we can write the following chemical equation:
And thus calculate the mass of silver nitrate that will produce the following mass of silver:
Next, we use the 2:2 mole ratio of silver to silver nitrate (silver ions source):
The step will be defined for the given mass of available silver nitrate which will be compared to 5.35 g (consumed mass) to see if they are the same (all consumed) or different (partial consumption).
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<u>Answer:</u> The mass percent of water in the original air sample is 4.16 %
<u>Explanation:</u>
We are given:
Volume of moist air = 12.0 L
Volume of dry air = 11.50 L
Volume of water lost = (12.0 - 11.50) L = 0.50 L
Here, the percent by mass ratio will be equal to the percent by volume ratio as the number of moles is directly related to the volume.
To calculate the volume percentage of water in the air, we use the equation:
Putting values in above equation, we get:
Hence, the mass percent of water in the original air sample is 4.16 %
The scientific notation is 5.98 * 10^-2
1) the element symbol, and thus name. For example, H is hydrogen, C is carbon and Fe is iron.
2) The atomic number, which is equal to the number of protons in the nucleus.
3) Since each proton has a +1 charge, you can also figure out the number of -1 electrons in the neutral atom.
4) The atomic mass, in atomic mass units, which is an average of 1 or more isotopes of the element.
Answer: The correct answer is C.
Explanation: Hope this helps plz mark brainliest.
