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gulaghasi [49]
3 years ago
6

Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation C

6H12O6(aq)+6O2(g)⟶6CO2(g)+6H2O(l) Calculate the number of grams of oxygen required to convert 48.0 g of glucose to CO2 and H2O. mass of O2: g Calculate the number of grams of CO2 produced. mass of CO2: g
Chemistry
1 answer:
Crank3 years ago
7 0

Answer:

70.3824 grams of carbondioxide is produced.

Explanation:

C_6H_{12}O_6(aq)+6O_2(g)⟶6CO_2(g)+6H_2O(l)

Moles of glucose =  \frac{48.0 g}{180 g/mol}=0.2666 mol

According to reaction 1 mole of glucose reacts with 6 mole of oxygen gas.

Then 0.2666 mol of gluocse will reactwith :

\frac{6}{1}\times 0.2666 mol =1.5996 mol of oxygen

Mass of 1.5996 moles of oxygen gas:

1.5996 mol\times 32 g/mol = 51.1872 g

51.1872 grams of oxygen are required to convert 48.0 grams of glucose to CO_2 and H_2O.

According to reaction, 1 mol, of glucose gives 6 moles of carbon dioxide.

Then 0.2666 moles of glucose will give:

\frac{6}{1}\times 0.2666 mol =1.5996 mol of carbon dioxide

Mass of 1.5996 moles of carbon dioxide gas:

1.5996 mol\times 44 g/mol = 70.3824 g

70.3824 grams of carbondioxide is produced.

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vova2212 [387]

Answer:

1.4 g/cm3

Explanation:

Density = Mass/Volume

Mass = 21g

Volume = 15cm3

Density = 21/15 = 1.4

8 0
2 years ago
Group the following electron configurations in pairs that would represent similar chemical properties at their atoms;
marishachu [46]

<u>Answer:</u> Pairs are:  (a) and (d), (b) and (f), (c) and (e)

<u>Explanation:</u>

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

Valence electrons are defined as the electrons which are present in the outermost shell of an atom. Outermost shell has the highest value of 'n' that is principal quantum number.

For the given options:

  • <u>For a:</u>

The given electronic configuration is:  1s^22s^22p^63s^2

The number of valence electrons in the given configuration are 2

  • <u>For b:</u>

The given electronic configuration is:  1s^22s^22p^63s^3

The number of valence electrons in the given configuration are [2 + 3] = 5

  • <u>For c:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^64s^23d^{10}4p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

  • <u>For d:</u>

The given electronic configuration is:  1s^22s^2

The number of valence electrons in the given configuration are 2

  • <u>For e:</u>

The given electronic configuration is:  1s^22s^22p^6

The number of valence electrons in the given configuration are [2 + 6] = 8

  • <u>For f:</u>

The given electronic configuration is:  1s^22s^22p^63s^23p^3

The number of valence electrons in the given configuration are [2 + 3] = 5

Electronic configuration of (a) and (d) will form a pair, (b) and (f) will form a pair, (c) and (e) will form a pair and will have similar chemical properties.

Hence, the pairs are:  (a) and (d), (b) and (f), (c) and (e)

4 0
3 years ago
Another name for the acid test ratio is the
elena55 [62]
Liquidity metric is the other name
4 0
3 years ago
You determine that Lauren's EER is 2200 kcal/day. You recommend and intake of 60% CHO, 15% protein, and 25% fat. Approximately h
const2013 [10]

Answer:

The answer to your question is 330 g of CHO

Explanation:

Data

Calories needed = 2200 kcal/day

CHO = 60%

Proteins = 15%

Fats = 25%

Grams of carbohydrates needed = ?

Process

1.- Calculate the number of calories  in 60% of 2200 kcal

                      2200 kcal ----------------  100%

                          x            ---------------      60%

                       x = (60 x 2200) / 100

                       x = 1320 kcal

2.- Calculate the grams of CHO

                       1 g of CHO ---------------- 4 kcal

                       x                 ----------------  1320 kcal

                       x = (1320 x 1) / 4

                       x = 1320/4

                       x = 330 g of CHO

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chubhunter [2.5K]
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6 0
2 years ago
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