Question

Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation C6H12O6(aq)+6O2(g)⟶6CO2(g)+6H2O(l) Calculate the number of grams of oxygen required to convert 48.0 g of glucose to CO2 and H2O. mass of O2: g Calculate the number of grams of CO2 produced. mass of CO2: g

Answer 1

Answer:

70.3824 grams of carbondioxide is produced.

Explanation:

$C_6H_{12}O_6(aq)+6O_2(g)⟶6CO_2(g)+6H_2O(l)$

Moles of glucose =  $\frac{48.0 g}{180 g/mol}=0.2666 mol$

According to reaction 1 mole of glucose reacts with 6 mole of oxygen gas.

Then 0.2666 mol of gluocse will reactwith :

$\frac{6}{1}\times 0.2666 mol =1.5996 mol$ of oxygen

Mass of 1.5996 moles of oxygen gas:

$1.5996 mol\times 32 g/mol = 51.1872 g$

51.1872 grams of oxygen are required to convert 48.0 grams of glucose to $CO_2$ and $H_2O$.

According to reaction, 1 mol, of glucose gives 6 moles of carbon dioxide.

Then 0.2666 moles of glucose will give:

$\frac{6}{1}\times 0.2666 mol =1.5996 mol$ of carbon dioxide

Mass of 1.5996 moles of carbon dioxide gas:

$1.5996 mol\times 44 g/mol = 70.3824 g$

70.3824 grams of carbondioxide is produced.