Hey there :)
All the options you have given are applicable.
Because xylem and phloem are essentials as they are the veins of the leaves. They are bundled together in thin strands. They allow the movement of water and nutrients.
The veins of leaves are finely branched to be in close contact with photosynthesizing cells as they need to store food.
Answer:
The correct option is C. It changes the three-dimensional structure of the active site so that ALAD is no longer compatible with its substrate.
Explanation:
Co-factors are molecules that are required by an enzyme to perform its function of catalysis. If a wrong co-factor binds to the enzyme then it will change the three-dimensional structure of the enzyme and the substrate will no longer fit into the enzyme. Hence, Option C is the best choice that explains the inhibition of ALAD.
Other options are false because :
Option A: The wrong co factor will not affect the substrate nor will it make it compatible for ALAD's active site.
Option B: The wrong factor doesn't change the amino acid sequence of the protein or enzyme, rather it changes the three dimensional structure of the enzyme.
Option D : The wrong co factor won't allow the reaction to proceed at a faster rate, rather it will inhibit the reaction.
Answer:
Voluntary muscles or striated muscles are those which are in our control.
ex, biceps, triceps, upper part of oesophagus., tongue.
On the way, the involuntary or non striated muscles are those which are not in control.
Ex, full ice of blood capillaries.
Answer:
500
Explanation:
According to the given information, the total number of albino people in the population= 1000/4 = 250.
Since albinism is an autosomal recessive trait, the genotype of albino people would be homozygous recessive. Therefore, the frequency of homozygous recessive genotype in the population (q2) = 250/1000= 0.25.
The frequency of recessive allele (q) = square root of 0.25 = 0.5
Since p+q=1. So, p (frequency of dominant allele) = 1-q = 1-0.5 = 0.5
Frequency of heterozygotes in the population= 2pq = 2 x 0.5 x 0.5 = 0.5 or 50%
Therefore, expected number of heterozygotes in the given population= 50% of 1000 = 500
