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dybincka [34]
3 years ago
11

In most acceptance sampling plans, when a lot is rejected, the entire lot is inspected and all defective items are replaced. Whe

n using this technique the AOQ: worsens (AOQ becomes a larger fraction). improves (AOQ becomes a smaller fraction). is not affected, but the AQL is improved. is not affected. falls to zero.
Mathematics
1 answer:
photoshop1234 [79]3 years ago
4 0

Answer:

When using this technique, the AOQ:

improves (AOQ becomes a smaller fraction).

Step-by-step explanation:

AOQ simply means Average Outgoing Quality, which improves with inspection.  It is a part of an organization's Acceptance Sampling Plan, usually designed to meet product quality and risk level targets.  The plan draws samples from a population of items.  Then it tests the samples.  It only accepts the entire population if the sample is considered good enough.  It also rejects the population when the sample is poor enough.  In the plan, information about sample size and critical acceptance or rejection numbers are clearly indicated.  Acceptance sampling is common in most business environments because it has been found to be more economical than doing 100% inspection of incoming production input and output.

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Braiist can someome pls explain i dont know
Greeley [361]

Answer:

G

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{m-n}

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\frac{n^{x} }{n^{y} } = n^{x-y}, then

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Since bases on both sides are equal, equate the exponents

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5 0
3 years ago
The perimeter of a triangle is 53 feet. One side of the triangle is 12 feet shorter than the second side. The third side is is 4
grandymaker [24]

Let the shortest side be = a, then side b = 2·a and side c = (b + 24)

We are given that a + b + c = 84

Substituting for b and c

a + 2·a + (a + 24) = 84

4·a + 24 = 84

4·a = 84 - 24 = 60

a = 60/4 = 15 feet

b = 2·15 = 30 feet

c = 15 + 24 = 39 feet


sorry if i am wrong

6 0
3 years ago
Read 2 more answers
Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with
skad [1K]

Parameterize S by the vector function

\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle

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Compute the outward-pointing normal vector to S :

\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle

The integral of the field over S is then

\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv

\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv

\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}

8 0
2 years ago
Please help me it’s a formative grade
sergejj [24]

Answer:

Step-by-step explanation: 800/x=100/17

(800/x)*x=(100/17)*x       - we multiply both sides of the equation by x

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