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3 years ago

Please help, I’ll mark as brainliest!! The picture is above :)

Mathematics

1 answer:

Ray Of Light [21]3 years ago

5 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable

Exact Form:

x = - 25/8 $\frac{x}{y}$

Decimal Form:

x = -3.125

Mixed Number Form:

x = - 3/1/8 $\frac{x}{y}$

Step-by-step explanation:

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xenn [34]

Step-by-step explanation:

You have $7,000 in your savings account gaining 4% interest per year. If you don't replace the $800 in the savings account

3 0

3 years ago

Rewrite 8(9 12) using the distributive property

frez [133]

First of all you have to use pemdas perentheses, exponents, multiplication, division, addition and subtraction. so 8 multiplied to nine and 9 multiplied to 12 and then add them together.

4 0

3 years ago

Find the value of x that makes m || n

USPshnik [31]

Answer:

x = 133

Step-by-step explanation:

x + 14 = 147

x (+ 14 - 14) = 147 - 14

x = 133

7 0

3 years ago

Read 2 more answers

5n-3=|n+9| HELP ME PLEASE

ehidna [41]

Answer:

n = 3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The attractive electric force between point charges q and -2q has a magnitude of 2.2 N when the separation

swat32

Answer:

The Magnitude of charge = q = 15.47 micro coulomb

Step-by-step explanation:

The attractive force between two points q and - 2 q = F = 2.2 Newton

The separation between two charges = 1.4 meters

Now from Coulomb's law = F = $(k \frac{q1 q2}{r^{2}})$ where k= $9 \times 10^{9}$ $\frac{N m^{2}}{c^{2}}$

So , 2.2 = $9 \times 10^{9}$ ( $(\frac{(q) ( - 2q)}{1.4^{2}})$

So , q ² = ( $\frac{0.479 \times 10^{-9}}{-2}$ )

For charge magnitude

I.e q ² = $2.395 \times 10^{-10}$

so, q = $1.547 \times 10^{-5}$

q = 15.47 \times 10^{-6} c

Or, q = 15.47 micro coulomb

Hence the Magnitude of charge = q = 15.47 micro coulomb Answer

4 0

4 years ago