For this case we have an equation of the form:
f (w) = A * (b) ^ w
Where,
A: initial amount
b: growth rate
w: number of weeks
Substituting values we have:
f (w) = 400 * (1.05) ^ w
Answer:
the beetle population can be determined after a number of weeks, w, with the following function:
f (w) = 400 * (1.05) ^ w
Answer:
two dimensional triangle
Step-by-step explanation:
im not smart but im pretty sure its that
Answer:
271,403 is rounded to 270,000 because the 1403 before it is less than 5000, 4 and below drop it down, 5 or more bump it up.
Step-by-step explanation:
This question is Incomplete
Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
Step-by-step explanation:
[ Refer to the attached file ]
( Slide to refer all files )
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• To solve Questions of type 11 we need to simplify the equation by using mathematical operations !!
• To solve Questions of type ( 13 , 15 and 17 ) we try to make the bar numeral to come other side of decimal
° and by subtracting we get the required fraction !!
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