What is 220 degrees celsius in fahrenheit?

Explain how to estimate the quotient using compatible<br>numbers.plz help fast

Nadya [2.5K]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

To estimate the quotient, make the fractions "like" fractions. To do this, you need to make the fractions have the same denominator, and turn them into improper fractions.

Step-by-step explanation:

$27\frac{2}{3} = 27 \frac{20}{30}$

$3\frac{9}{10} = 3\frac{27}{30}$

Now the denominators are the same --> they are "like" fractions.

$27\frac{20}{30} + 3\frac{27}{30} = ?$

$27\frac{20}{30} + 3\frac{27}{30} = (27 + 3) + (\frac{20}{30} + \frac{27}{30})$

$27\frac{20}{30} + 3\frac{27}{30} = (30) + (\frac{47}{30})$

$27\frac{20}{30} + 3\frac{27}{30} = (30) + (1 \frac{17}{30})$

$27\frac{20}{30} + 3\frac{27}{30} = 31 \frac{17}{30}$

Your answer is $31\frac{17}{30}$ .

I hope this helps!

3 0

3 years ago

. A trader bought A TV set for Birr 2000 and sold it at loss of 11/2% what:was the selling price?

olga nikolaevna [1]

Answer:

1890

Step-by-step explanation:

Loss = 11/2 % = 5.5 %

Cost price = 2000

Loss = 5.5% of cost price

= 5.5% * 2000

$= \frac{5.5}{100}*2000\\\\= 5.5*20\\= 110$

Selling price = Cost price - loss

= 2000 - 110

= 1890

6 0

3 years ago

The Wall Street Journal reported that automobile crashes cost the United States $162 billion annually (2008 data). The average c

ivanzaharov [21]

Answer:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma= 500$ represent the population standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =120 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The confidence2 level is 98% or 0.98 then the significance level would be $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , the critical value for this case would be $z_{\alpha/2}=2.326$ , replacing into formula (b) we got:

$n=(\frac{2.326(500)}{120})^2 =93.928 \approx 94$

So the answer for this case would be n=94 rounded up to the nearest integer

8 0

3 years ago

In the year 2002, the world population was estimated at 6 billion people. Based on research from the World Bank, about 20% lived

olga_2 [115]

In the given question all the information's are provided based on which the answer to the question can be easily deduced. It is already given that the population of the world in the year 2002 was estimated to about 6 billion. Among them 20% of the people lived on an an income of less that $1 per day.Firstly let us convert 6 billion from words to numbers.
6 billion = 6000000000
Now
Number of people earning less that $1 per day = (20/100) * 6000000000
= 6000000000/5
= 1200000000
So the number of people earning less than $1 per day is 1200000000

8 0

2 years ago

PLEASE HELP ASAP!!!! 50 POINTS!!

Kamila [148]

Answer:

Hope this helps!!

Step-by-step explanation:

2ya and 2yb where a and b have no common factors and a and b are polynomaals

a=(x+2)(x+3)

b=(x+4)(x+5)

no common factors betwen a and b

so

2ya=2y(x+2)(x+3)=2yx²+10xy+12y

2yb=2y(x+4)(x+5)=2yx²+18xy+40y

the 2 polynomials are 2yx²+18xy+40y and 2yx²+10xy+12y

4 0

2 years ago

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