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3 years ago

What determines whether an object will scatter light or reflect light?

1 answer:

4 0

Other factors that affect how much light is absorbed, reflected and scattered concerns the light itself and how it arrived at the surface of the object, such as the wavelength (color) of the light, and. the angle at which it reaches the surface.

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Round to 4 significant figures. 35.5450

Masja [62]

Answer:

35.5450 will be rounded to 35.55

Explanation:

=35.5450

if the last digit is less than 5 then it will be ignored

=35.545

when the dropping digit is 5 then the retaining digit will increse by a factor of 1

=35.55

i hope this will help you

3 0

3 years ago

Read 2 more answers

Which best describes a similarity between power plants that use water as an energy source and those that use wind as an energy s

elixir [45]

Answer:

Both use kinetic energy to produce electricity.

6 0

2 years ago

sergey [27]

The correct option would be 3.

Only thermal energy changes

Hope this helps you

Brainliest would be appreciated

-AaronWiseIsBae

5 0

2 years ago

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If the ph of a solution is decreased from ph 8 to ph 6 it means that the

saw5 [17]

Explanation:

Relation between pH and concentration of hydrogen ions is as follows.

pH = $-log [H^{+}]$

So, it means that an increase in the value of pH will show that there occurs a decrease in concentration of hydrogen ions.

Therefore, the solution becomes basic in nature.

On the other hand, a decrease in the value of pH will show that there occurs an increase in the concentration of hydrogen ions.

Therefore, the solution becomes more acidic in nature.

Hence, if the pH of a solution is decreased from pH 8 to pH 6 it means that the concentration of hydrogen ions has increased in the solution.

5 0

3 years ago

Read 2 more answers

PLEASE HELP ME SOLVE THIS.Thank you so much!

Tju [1.3M]

Answer: The coefficients for the given reaction species are 1, 6, 2, 3.

Explanation:

The given reaction equation is as follows.

$Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}$

Now, the two half-reactions can be written as follows.

Reduction half-reaction: $Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}$

This will be balanced as follows.

$Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O$ ... (1)

Oxidation half-reaction: $Cl^{-} \rightarrow Cl_{2} + 1e^{-}$

This will be balanced as follows.

$6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-}$ ... (2)

Adding both equation (1) and (2) we will get the resulting equation as follows.

$Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O$

Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.

6 0

2 years ago