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ziro4ka [17]
3 years ago
15

In which environment would the shell of an organism most likely be preserved as a fossil?

Chemistry
2 answers:
maxonik [38]3 years ago
7 0

Answer:

D. at the bottom of the lake buried by a landslide.

Explanation:

Hello,

Fossils are known as the ancient remains of the animals or plants that lived on earth so long ago. They are produced when different tissues of plants and animals parts are decomposed by microorganisms present in the soil, in addition to hard remains of bones, wood, shells and exoskeletons that are still accumulated. Such remains are usually buried under several layers of soil and debris, thus, they get compacted and consequently transformed into rocks.

Now, the most suitable environment for the preservation of fossil remains is at the bottom of a lake buried by a landslide, since the several layers get deposited over the fossil remains, taking care of them and subsequently promoting fossil preservation.

Best regards.

ValentinkaMS [17]3 years ago
5 0
D.) At the bottom of a lake buried by a landslide
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An exothermic reaction is a type of reaction that dissipates heat as the reaction proceeds. This would mean that in a closed system, when a reaction proceeds and is endothermic, the temperature of the solution  or the system would increase so as to maintain the equilibrium with the whole system.
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3 years ago
What is the percent yield of a reaction in which 200. g of phosphorus trichloride reacts with excess water to form 91.0 g of hcl
Snowcat [4.5K]
Answer is: <span>yield of a reaction is 56,4%.
</span>Chemical reaction: PCl₃ + 3H₂O → 3HCl + H₃PO₃.
m(PCl₃) = 200 g.
m(HCl) = 91,0 g.
n(PCl₃) = m(PCl₃) ÷ M(PCl₃).
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n(HCl) = m(HCl) ÷ M(HCl).
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4 0
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Read 2 more answers
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What is the formula for lead carbonate?
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mamaluj [8]

<u>Answer:</u> The volume of bone for given sample is 30.49cm^3

<u>Explanation:</u>

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

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Putting values in above equation, we get:

0.82g/cm^3=\frac{25g}{\text{Volume of bone}}\\\\\text{Volume of bone}=30.49cm^3

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