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Mashcka [7]
3 years ago
13

Calculate the molar mass of a gaseous substance if 0.125 g of the gas occupies 93.3 mL at STP.

Chemistry
1 answer:
just olya [345]3 years ago
7 0

Answer:

30.0g/mol

Explanation:

Step 1: Given data

  • Mass of the gas: 0.125 g
  • Pressure (P): 1 atm (standard pressure)
  • Temperature (T): 273.15 K (standard temperature)
  • Volume (V): 93.3 mL

Step 2: Calculate the moles of the gas

We will use the ideal gas equation.

P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{1atm \times 0.0933L}{\frac{0.0821atm.L}{mol.K}  \times 273.15K} = 4.16 \times 10^{-3} mol

Step 3: Calculate the molar mass of the gas

4.16 × 10⁻³ moles correspond to a mass of 0.125 g. The molar mass of the gas is:

\frac{0.125g}{4.16 \times 10^{-3} mol} =30.0g/mol

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A simple way to determine which reagent is the limiting reactant is to convert all given data to moles then divide by the respective coefficients of the balanced equation. The smaller value will be the limiting reactant.

                 4FeCl₃     +   3O₂     => 2Fe₂O₃+ 6Cl₂

Given =>  7/4 = 1.75*     9/3 = 3

*Smaller value => FeCl₃ is limiting reactant.  

NOTE: However, when working problems, one must use original mole values given.

   

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6 0
3 years ago
500 mL of water is added to 400 mL of 0.35 M HCl. Find the concentration of the diluted solution.
jarptica [38.1K]

The concentration of diluted solution is 0.16 M

<u>Explanation:</u>

As, the number of moles of diluted solution and concentrated solution will be same.

So, the equation used to calculate concentration will be:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=0.35M\\V_1=400mL\\M_2=?M\\V_2=(500+400)mL=900mL

Putting values in above equation, we get:

0.35\times 400=M_2\times 900\\\\M_2=\frac{0.35\times 400}{900}=0.16M

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5 0
3 years ago
What is the net ionic equation for the reaction if any that occurs when aqueous solutions of Na2CO3 and HCL are mixed?
strojnjashka [21]

Answer:

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

Explanation:

The balanced reaction between Na2CO3 and HCl is given as;

Na₂CO₃ (aq) + 2 HCl (aq) → 2 NaCl (aq) + CO₂ (g) + H₂O (l)

The next step is o express the species as ions.

The complete ionic equation for the above  reaction would be;

2Na⁺(aq)  + CO₃²⁻(aq)  +  2H⁺(aq)  + 2Cl⁻(aq)   → Na⁺(aq)  + Cl⁻(aq)  + CO₂ (g)  + H₂O (l)

The next step is to cancel out the spectator ion ions; that is the ions that appear in both the reactant and product side unchanged.

The spectator ions are;  Na⁺ and Cl⁻

The net ionic equation is given as;

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

7 0
3 years ago
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