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Mashcka [7]
3 years ago
13

Calculate the molar mass of a gaseous substance if 0.125 g of the gas occupies 93.3 mL at STP.

Chemistry
1 answer:
just olya [345]3 years ago
7 0

Answer:

30.0g/mol

Explanation:

Step 1: Given data

  • Mass of the gas: 0.125 g
  • Pressure (P): 1 atm (standard pressure)
  • Temperature (T): 273.15 K (standard temperature)
  • Volume (V): 93.3 mL

Step 2: Calculate the moles of the gas

We will use the ideal gas equation.

P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{1atm \times 0.0933L}{\frac{0.0821atm.L}{mol.K}  \times 273.15K} = 4.16 \times 10^{-3} mol

Step 3: Calculate the molar mass of the gas

4.16 × 10⁻³ moles correspond to a mass of 0.125 g. The molar mass of the gas is:

\frac{0.125g}{4.16 \times 10^{-3} mol} =30.0g/mol

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Explanation :

Graduated cylinder : It is a measuring cylinder that is used to measure the volume of a liquid. It has a narrow cylindrical shape. The marked line drawn on the graduated cylinder shows the amount of liquid that has been measured.

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The mass of carbon dioxide that would be made by reacting 30 grams C2H6 with 320 grams O2 will be 80 grams

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Since the mole of C2H6 is 1, the equivalent mole of CO2 would, therefore, be 2.

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More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults

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