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3 years ago

PLEASE HELP!! WILL MARK BRAINLIEST!!!!! please answer all to get brainliest!

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

5 0

Answer:

1. -1

2. n>-4

3. -5>y

4. -30>x ( i didn't know how to put the line under > but it should have a line under it)

Step-by-step explanation:

Basile [38]3 years ago

5 0

Answer:

-30

Step-by-step explanation:

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Iris is building a model of the Washington Monument. Her model measures 15 in. tall and is 1.5 in. wide at the base. The actual

irina [24]

Using how tall it is over how wide
=>tall/wide
The model 15in/1.5in
The actual x/55ft

Convert everything into the same units so 55ft to inches
There are 12in in 1ft
55ft * 12in/1ft
The ft cross out leaving in
55*12in= 660 in

So
15in/1.5in = x/660in
Now solve for x my multiplying both side by 660in
660in *15in/1.5in=x
x= 6600in tall

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2 years ago

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PLEASE HURRY!!! TIMED!!!! WILL GIVE BRAINLIEST!!!

fgiga [73]

Answer:

7.608

Step-by-step explanation:

An irrational number is any number which can't be written as a fraction this way. For example, pi and the square root of two cannot be expressed as a fraction of two whole numbers, so they are both irrational.

if we make the respective accounts in the first and second problem we will see that they are irrational numbers

the fourth is a periodic number, which falls within the irrational

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2 years ago

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Ally sold 18 boxes of girl scout cookies. This was 40% of the number of boxes that Kayla sold. How many boxes did Kayla sell?

S_A_V [24]

Answer:

Kayla sold 90 boxes of cookies.

Step-by-step explanation:

let's have X be the number of boxes Kayla sold.

x⇒100%

18⇒20%

Find x,

x=100/20 × 18

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2 years ago

30% of what number is 13.8?

Feliz [49]

The answer is 4.14 hoped that helped

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2 years ago

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Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

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3 years ago