All categories

2 years ago

What can affect the reaction RATE but not the rate constant?

Chemistry

1 answer:

Gnesinka [82]2 years ago

4 0

Answer/Explanation:

The rate of a reaction depends on the rate constant and concentration the rate constant according to Arrhenius is as u stated. An increase in temperature increases the rate constant and hence the rate. An increase in concentration increases the rate but not the rate constant.

You might be interested in

What is the origin of the word hydrogen?

soldi70 [24.7K]

The origin is greek and English

6 0

2 years ago

Two identical containers, one red and one yellow, are inflated with different gases at the same volume and pressure. Both contai

Evgen [1.6K]

Answer:

Explanation:

Here we're dealing with the root mean square velocity of gases. We'll provide the formula in order to calculate the root mean square velocity of a gas:

$v_{rms}=\sqrt{\frac{3RT}{M}}$

Here:

$R = 8.314 \frac{J}{K mol}$ is the ideal gas law constant;

$T$ is the absolute temperature in K;

$M$ is the molar mass of a compound in kg/mol.

We know that the gas from the red container is 4 times faster, as it takes 4 times as long for the yellow container to leak out, this means:

$\frac{v_{rms, red}}{v_{rms, yellow}} = 4$

We also know that the temperature of the red container is twice as large:

$\frac{T_{red}}{T_{yellow}} = 2$

Write the ratio of the velocities and substitute the variables:

$\frac{v_{rms, red}}{v_{rms, yellow}}=\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=4$

Then:

$\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=\sqrt{\frac{3RT_{red}}{M_{red}}\cdot \frac{M_{yellow}}{3RT_{yellow}}}=\sqrt{\frac{T_{red}}{T_{yellow}}\cdot \frac{M_{yellow}}{M_{red}}}=4$

From here:

$16 = \frac{T_{red}}{T_{yellow}}\cdot \frac{M_{yellow}}{M_{red}}$

Then:

$\frac{M_{yellow}}{M_{red}} = \frac{16}{\frac{T_{red}}{T_{yellow}}} = \frac{16}{2} = 8$

5 0

2 years ago

What is the hybridization of the central atom, electron geometry, and molecular geometry of H3CCCH?

DIA [1.3K]

Answer:

Hybridization: sp

Electron geometry: linear

Molecular geometry: linear

Explanation:

H₃CCCH can also be written as its Lewis structure which is shown in the figure attached. The figure shows that the central carbon atom makes a single bond with CH₃ and a triple bond with CH. This means that the hybridization of the carbon is sp and both the electron and molecular geometry are linear with an 180° bond angle.

6 0

3 years ago

Wofür steht die Abkürzung „PUR“?

Lunna [17]

Explanation:

polyurethane, a polymer

8 0

2 years ago

Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.

Ad libitum [116K]

Explanation:

The given data is as follows.

Concentration = 0.1 $mol/dm^{3}$

= 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

= $6.022 \times 10^{25} ions/m^{3}$

T = $30^{o}C$ = (30 + 273) K = 303 K

Formula for electric double layer thickness ( $\lambda_{D}$ ) is as follows.

$\lambda_{D}$ = $\frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}$

where, $n^{o}$ = concentration = $6.022 \times 10^{25} ions/m^{3}$

Hence, putting the given values into the above equation as follows.

$\lambda_{D}$ = $\sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}$

= $\sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}$

= $9.669 \times 10^{-10}$ m

or, = $9.7 A^{o}$

= 1 nm (approx)

Also, it is known that $\lambda_{D}$ = $\sqrt \frac{1}{n^{o}}$

Hence, we can conclude that addition of 0.1 $mol/dm^{3}$ of KCl in 0.1 $mol/dm^{3}$ of NaBr " $\lambda_{D}$ " will decrease but not significantly.

7 0

2 years ago