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Radda [10]
3 years ago
14

What can affect the reaction RATE but not the rate constant?

Chemistry
1 answer:
Gnesinka [82]3 years ago
4 0

Answer/Explanation:

The rate of a reaction depends on the rate constant and concentration the rate constant according to Arrhenius is as u stated. An increase in temperature increases the rate constant and hence the rate. An increase in concentration increases the rate but not the rate constant.

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When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2
masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

7 0
4 years ago
How many atoms are in 163 g of calcium?
I am Lyosha [343]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles.

163 g Ca (1 mol / 40.08 g) ( </span>6.022 x 10^23 atoms / 1 mol ) = 2.45 x10^24 atoms Ca
8 0
3 years ago
Read 2 more answers
A 5 cm3 piece of aluminum has a higher density than a 10cm3 of aluminum. True or false
Lubov Fominskaja [6]

Density stays the same, false

3 0
2 years ago
The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an
ser-zykov [4K]

Answer:

24540\frac{mg}{m^3}

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

\frac{3L\ CO}{L\ gas}

By using the ideal gas equation we compute the density of CO:

\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L

Then we apply the conversion factors as follows:

=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}

Regards.

4 0
3 years ago
the trunk of a certain tree is 50 cm thick. Each year it gets thicker by 1 cm. How thick will the tree trunk be in 50 years
Mama L [17]
100 centimeters thick

Starting thickness was 50 cm
1 cm every 50 years= 1x50
1x50=50
Old thickness + New thickness= 50 + 50 = 100 cm
:)
5 0
3 years ago
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