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3 years ago

Draw the skeletal (line-angle) structure for 2,2-dimethyl-4-propyloctane.

Chemistry

1 answer:

Allisa [31]3 years ago

6 0

Answer :

Total carbons are in the structure = 13

Primary carbons are in the structure = 5

Secondary carbons are in the structure = 6

Tertiary carbons are in the structure = 1

Quaternary carbons are in the structure = 1

Explanation :

Primary carbon : It is a carbon atom that is bound to only 1 carbon atom.

Secondary carbon : It is a carbon atom that is bound to 2 carbon atom.

Tertiary carbon : It is a carbon atom that is bound to 3 carbon atom.

Quaternary carbon : It is a carbon atom that is bound to 4 carbon atom.

As we are given the name of compound is, 2,2-dimethyl-4-propyloctane.

In this compound, eight carbon are align in a straight line, two methyl group are attached at 2nd position of the carbon in main chain and a propyl group that is three membered carbon chain is attached at 4th position of the carbon in main chain.

The given compound skeletal structure is shown below.

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Using the data, which of the following is the rate constant for the rearrangement of methyl isonitrile at 320 ∘C? (HINT: the act

svp [43]

Explanation:

Below is an attachment containing the solution.

3 0

3 years ago

mass of 6.584 g. After it is heated, it has a mass of 4.194 g. What is the percentage by mass of water in the hydrate?

Bad White [126]

M₁=6.584 g
m₂=4,194 g

m(H₂O)=m₁-m₂

w(H₂O)=m(H₂O)/m₁

w(H₂O)=(m₁-m₂)/m₁

w(H₂O)=(6.584-4.194)/6.584=0.3630 (36.30%)

the percentage by mass of water in the hydrate 36.30

8 0

3 years ago

What are the main reasons that organic chemistry is a primarily target for "green chemistry"? I. Organic solvents are often flam

Debora [2.8K]

Answer: Option 1 and 11

1. Organic solvents are often flammable.

II. Organic solvents are often toxic.

Explanation:

Organic solvents are often flammable and Organic solvents are often toxic are the reasons why organic chemistry is a primary target of green chemistry because green chemistry is the use of principles or approach to remove hazardous or toxic substances from chemical.profuctd or processes to make them fit or safe for use and the solvents of organic chemist are toxic, therefore green chemistry remove the toxic substances.

8 0

3 years ago

Sample Response: The change in her position (from beginning to end), along with the direction, is considered her displacement. T

kykrilka [37]

The sample response given in the question is right.

To find the answer, we need to know more about the distance and displacement.

<h3>How distance differ from displacement?</h3>

Displacement is the shortest distance between the initial and final points of a body.
It is the change in position with a fixed direction.
Displacement is a vector quantity and can be positive, negative or zero values.
Distance is the length of actual path of the body between initial and final positions.
It's a scalar quantity and it can be positive or zero.
The magnitude of displacement is less than or equal to the distance travelled.

Thus, we can conclude that the given sample response is right.

Learn more about distance here:

brainly.com/question/28124225

#SPJ1

3 0

2 years ago

EXTRA POINTSSS 1. A solution at 25 degrees Celsius is 1.0 × 10–5 M H3O+. What is the concentration of OH– in this solution?

AlekseyPX

Answer:

Concentration of OH⁻:

1.0 × 10⁻⁹ M.

Explanation:

The following equilibrium goes on in aqueous solutions:

$\text{H}_2\text{O}\;(l)\rightleftharpoons \text{H}^{+}\;(aq) + \text{OH}^{-}\;(aq)$ .

The equilibrium constant for this reaction is called the self-ionization constant of water:

$K_w = [\text{H}^{+}]\cdot[\text{OH}^{-}]$ .

Note that water isn't part of this constant.

The value of $K_w$ at 25 °C is $10^{-14}$ . How to memorize this value?

The pH of pure water at 25 °C is 7.
$[\text{H}^{+}] = 10^{-\text{pH}} = 10^{-7}\;\text{mol}\cdot\text{dm}^{-3}$
However, $[\text{OH}^{-}] = [\text{H}^{+}]=10^{-7}\;\text{mol}\cdot\text{dm}^{-3}$ for pure water.
As a result, $K_w = [\text{H}^{+}] \cdot[\text{OH}^{-}] = (10^{-7})^{2} = 10^{-14}$ at 25 °C.

Back to this question. $[\text{H}^{+}]$ is given. 25 °C implies that $K_w = 10^{-14}$ . As a result,

$\displaystyle [\text{OH}^{-}] = \frac{K_w}{[\text{H}^{+}]} = \frac{10^{-14}}{1.0\times 10^{-5}} = 10^{-9} \;\text{mol}\cdot\text{dm}^{-3}$ .

8 0

3 years ago