Question

A strip of copper 370 μm thick and 4.5 mm wide is placed in a uniform magnetic field B with arrow of magnitude 0.30 T, with B with arrow perpendicular to the strip. A current i = 24 A is then sent through the strip such that a Hall potential difference V appears across the width of the strip. Calculate V. (The number of charge carriers per unit volume for copper is 8.47 ✕ 1028 electrons/m3.)

Answer 1

Explanation:

The given data is as follows.

              Magnetic field (B) = 0.30 T

              Current (I) = 24 A

              n = $370 \times 10^{-6} m$

            charge on electron (e) = $1.602 \times 10^{-19}$ C

Formula to calculate the potential difference is as follows.

            V = $\frac{B \times I/d}{n \times e }$

                = $\frac{0.30 T \times 24 amps}{8.47 \times 10^{28} electrons/ m^{3} \times 370 \times 10^{-6} m \times 1.602 \times 10^{-19} C)}$

                = $1.38 \times 10^{-6}$ V

Therefore, we can conclude that value of potential difference is $1.38 \times 10^{-6}$ V.