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Nat2105 [25]
3 years ago
14

A strip of copper 370 μm thick and 4.5 mm wide is placed in a uniform magnetic field B with arrow of magnitude 0.30 T, with B wi

th arrow perpendicular to the strip. A current i = 24 A is then sent through the strip such that a Hall potential difference V appears across the width of the strip. Calculate V. (The number of charge carriers per unit volume for copper is 8.47 ✕ 1028 electrons/m3.)
Chemistry
1 answer:
777dan777 [17]3 years ago
8 0

Explanation:

The given data is as follows.

              Magnetic field (B) = 0.30 T

              Current (I) = 24 A

              n = 370 \times 10^{-6} m

            charge on electron (e) = 1.602 \times 10^{-19} C

Formula to calculate the potential difference is as follows.

            V = \frac{B \times I/d}{n \times e
}

                = \frac{0.30 T \times 24 amps}{8.47 \times 10^{28} electrons/ m^{3} \times 370 \times 10^{-6} m \times 1.602 \times 10^{-19} C)}

                = 1.38 \times 10^{-6} V

Therefore, we can conclude that value of potential difference is 1.38 \times 10^{-6} V.

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