Based on the charge on the aluminium ion, 0.9 g of aluminium are deposited by 0.1 F of electricity.
<h3>What is electrolysis?</h3>
Electrolysis is the decomposition of a substance known as an electrolyte when electric current is passed through it.
The mass and hence moles an electrolyte deposited when current is passed through it depends on the charge on the ion.
Aluminium ion has a charge of +3 and requires 3F of electricity to deposit 1 mole or 27 g of aluminium
0.1 F will discharge = 0.1/3 × 27 g of aluminium
mass of aluminium deposited = 0.9 g of aluminium.
Therefore, 0.9 g of aluminium are deposited by 0.1 F of electricity.
Learn more about electrolysis at: brainly.com/question/26050361
Answer:
35Cl = 75.9 %
37Cl = 24.1 %
Explanation:
Step 1: Data given
The relative atomic mass of Chlorine = 35.45 amu
Mass of the isotopes:
35Cl = 34.96885269 amu
37Cl = 36.96590258 amu
Step 2: Calculate percentage abundance
35.45 = x*34.96885269 + y*36.96590258
x+y = 1 x = 1-y
35.45 = (1-y)*34.96885269 + y*36.96590258
35.45 = 34.96885269 - 34.96885269y +36.96590258y
0.48114731 = 1,99704989y
y = 0.241 = 24.1 %
35Cl = 34.96885269 amu = 75.9 %
37Cl = 36.96590258 amu = 24.1 %
Answer:
P = 5.14ATM
Explanation:
Number of moles = 0.108moles
Temperature (T) = 20°C = 20 + 273.15 = 293.15K
Volume V = 0.505L.
Pressure (P) = ?
R = 0.082J/mol.K
From ideal gas equation,
PV = nRT
P = nRT / V
P = (0.108 * 0.082 * 293.15) / 0.505
P = 2.596 / 0.505
P = 5.14ATM
The pressure of the gas is 5.14ATM
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Ir = [Xe] 4f14 5d7 6s2
<span>Rn = [Xe] 4f14 5d10 6s2 6p6 </span>
<span>Fe = [Ar] 3d6 4s2 </span>
<span>Pa = [Rn] 5f2 6d1 7s2 </span>
<span>Y = [Kr] 4d1 5s2 </span>
<span>Re = [Xe] 4f14 5d5 6s2 </span>
<span>So only Rhenium (Re) has an electronic configuration where the d orbital has 5 electrons in it.</span>
