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astraxan [27]
3 years ago
15

How is thermal energy transferred during conduction? Check all that apply.

Chemistry
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

Option 2, 3, and also 6 btw

Explanation:

The other guy was wrong

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Gasoline has a density of 0.749 g/ml. how many pounds does 19.2 gallons of gasoline weigh?
Svetradugi [14.3K]
A good first step is writing the amount in terms of ml. 

19.2 gallons = 72.68 L = 72680 ml

that would mean it weighs 0.749*720680g = 54437.32ml = 54.437 L

hope that helps :)
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The answer is B. Fungi,Protists
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If half of the moon is always illuminated why does its appearance from earth change?
irina [24]

Answer:

The different angles the moon has from sunlight to the earth

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A gas occupies a volume of 650.0 mL when the pressure is 3.50 atm. What will the new volume be if the pressure is reduced to 1.6
Gemiola [76]

The new volume will be 1379 mL.

Explanation:

As per Boyle's law, the product of initial volume and initial pressure of any gas molecule is equal to the product of final volume and final pressure of those molecules.

So here the initial volume is 650 ml and the initial pressure is 3.50 atm. As the temperature is said to be constant, then this system will be obeying Boyle's law. So, the final pressure is given as 1.65 atm. As there is a reduction in the pressure, the volume of the gas is tend to get expanded.

P_{1} V_{1} = P_{2} V_{2}

So, (650*10^{-3}*3.50)=(1.65*V_{2})

V_{2} = \frac{650*10^{-3}*3.50}{1.65} = 1379 mL

So, the new volume of the gas on reduction in pressure is 1379 mL.

7 0
3 years ago
Calculate the final Celsius temperature when 634 L at 21 °C is compressed to 307 L.
Illusion [34]

Answer:

- 130.64°C.

Explanation:

  • We can use the general law of ideal gas:<em> PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

<em>V₁T₂ = V₂T₁</em>

<em></em>

V₁ = 634.0 L, T₁ = 21.0°C + 273 = 294.0 K.

V₂ = 307.0 L, T₂ = ??? K.

<em>∴ T₂ = V₂T₁/V₁ </em>= (307.0 L)(294.0 K)/(634.0 L) = <em>142.36 K.</em>

<em>∴ T₂(°C) = 142.36 K - 273 = - 130.64°C.</em>

5 0
3 years ago
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