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marshall27 [118]
3 years ago
14

Paige borrows $4000 at an interest rate of 12% per year what is the amount due at the end of 3 years

Mathematics
1 answer:
lesya692 [45]3 years ago
5 0

For this case we have an equation of the form:

y = A * (b) ^ x

Where,

A: initial loan

b: interest rate

x: number of years

Substituting values we have that the function that models the problem is:

y = 4000 * (1.12) ^ x

By the end of the third year we have:

y = 4000 * (1.12) ^ 3\\y = 5619,712

Answer:

the amount due at the end of 3 years is:

y = 5619,712

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Answer Question QUICKILY please
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5 0
3 years ago
H and J are both between G and K such that GH = JK and H is between G and J.
DIA [1.3K]

Answer:

32

Step-by-step explanation:

So the order of the points is: GHJK

GH = x+10 =JK

HJ=8

JK=2x-4

JK = x+10=2x-4

x+10=2x-4

10+4=2x-x

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6 0
3 years ago
three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.
jasenka [17]
X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
=93

3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)
7 0
3 years ago
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