Why does the momentum before a collision equal the momentum after a collision?
2 answers:
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Answer:
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas at STP = 1 atm
= final pressure of gas = 2.67 atm
= initial volume of gas =
= final volume of gas = ?
= initial temperature of gas at STP =
= final temperature of gas =
Now put all the given values in the above equation, we get:
Thus the final volume will be
Answer:
Explanation:
In order to find its centripetal acceleration we need to use the next equation:
So, we need to find its velocity in first place. Considering that the time T required for one complete revolution is called the period. For constant speed is given by:
Solving for v, considering that in this case T=1.3min=78s, and r=242
Finally, replacing v in the centripetal acceleration equation:
Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736
Explanation:
According to the Arrhenius equation,
or,
where,
= rate constant at 525K
= rate constant at 545K
= activation energy for the reaction = 185kJ/mol= 185000J/mol (1kJ=1000J)
R = gas constant = 8.314 J/mole.K
= initial temperature = 525 K
= final temperature = 545 K
Now put all the given values in this formula, we get
Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736