Answer:
0.0062 Nm
Explanation:
Parameters given:
Number of turns, N = 1
Current, I = 16.5 mA = 0.0165 A
Circumference of loop = 2.55 m
Magnetic field strength, B = 0.720 T
The torque exerted by a magnetic field is given as:
τ = N * I * A * B * sinθ
θ = angle between the perpendicular of the loop to the magnetic field (90° in this case)
Where A = area of loop.
First we find the radius of the loop:
Circumference = 2.55 = 2 * pi * r
=> r = 2.55/(2 * 3.142)
r = 0.406
Area = pi * r²
Area = 3.142 * 0.406²
Area = 0.52 m²
Therefore, torque is:
τ = 1 * 0.0165 * 0.52 * 0.72 * sin90
τ = 0.0062 Nm
