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galben [10]
3 years ago
13

Calculate either [H3O ] or [OH–] for the solutions below at 25 C.

Chemistry
2 answers:
Marysya12 [62]3 years ago
5 0
Answer is: concentration of hydronium ions is 5,5·10⁻⁸ M.
[OH⁻] = 1,83·10⁻⁷ M; equilibrium concentration.
The Kw (the ionic product for water) at 25°C is 1·10⁻¹⁴ mol²/dm⁶ or 1·10⁻¹⁴ M².<span>
Kw = [H</span>₃O⁺] · [OH⁻].
[H₃O⁺] = Kw ÷ [OH⁻].
[H₃O⁺] = 1·10⁻¹⁴ M² ÷ 1,83·10⁻⁷ M.
[H₃O⁺] = 5,5·10⁻⁸ M.
Fittoniya [83]3 years ago
5 0

This problem requires using the concept of pH and pOH. The “p” stands for the negative log so pH and pOH represent the negative log of the concentration of hydrogen or hydroxide ions.

Here is the solution:

pOH = -log [OH-]

pOH = -log [1.83x10^-7 M]

pOH = 6.74

 

pH + pOH = 14

pH = 14 - 6.74

pH = 7.26

 

pH = -log [H3O+]

7.26 = -log[H3O+]

[H3O+] = 5.46 x 10^-8 M

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A 1.000 g sample of an unknown hydrate of cobalt chloride is gently dehydrated. The resulting mass is 0.546 g. The cobalt is iso
ira [324]

Answer:

Explanation:

From the 1 g sample you have:

0.546 grams of cobalt chloride

1-0.546=0.454 grams of water

Now:

1) The salt

Of the 0.546 g, 0.248 g are cobalt (Mr=58.9) and the rest id Cl (Mr=35.45):

n_{Co}=\frac{0.248 g}{58.9 g/mol}=4.21*10^{-3}mol

n_{Cl}=\frac{0.298 g}{35.45g/mol}=8.4*10^{-3}mol

Dividing:

\frac{n_{Cl}}{n_{Co}}=\frac{8.4*10^{-3}mol}{4.21*10^{-3}mol}=2

So the molecular formula will be:

CoCl_2

2) The water

The water's molecular weight is M=18 :

n_{w}=\frac{0.454g}{18g/mol}=0.025 mol

Bonding with the Co:

\frac{n_{w}}{n_{Co}}=\frac{0.025mol}{4.21*10^{-3}mol}=6

The complete formula of the hydrate:

CoCl_2*6 H_2O

8 0
4 years ago
Why are all of the substances on the periodic table classified as elements?
natta225 [31]

Because just like compounds, the table of chemicals can be looked at as having all the different pieces of it.  So the different chemicals are the different "elements" to the periodic table.

6 0
3 years ago
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qzasui

Explanation:

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3 0
3 years ago
Where are elements that form molecules of two of the same atoms commonly found on the periodic table?
Sveta_85 [38]
Elements that form diatomic molecules, or molecules of two atoms each, are commonly found on the right side of the periodic table.
6 0
3 years ago
Read 2 more answers
How many grams of Cl are in 535 g of CaCl₂?
Sliva [168]
The answer is 341.7 g.

(1) Calculate the molar mass (M) of CaCl2 which is the sum of atomic masses (A) of elements:
M(CaCl2) = A(Ca) + 2A(Cl)
A(Ca) = 40.1 g/mol
A(Cl) = 35.45 g/mol

M(CaCl2) = 40.1 + 2 * 35.45 = 40.1 + 70.9 = 111 g/mol

(2) Calculate in how many moles are 535 g:
M(CaCl2) = 111 g/mol
111g : 1mol = 535 g : xmol
x = 535 g * 1mol : 111g = 4.82 mol

(3) Calculate how many grams of Cl are in 4.82 mol:
A(Cl) = 35.45 g/mol 
2A(Cl) = 2 * 35.45 = 70.9 g/mol
70.9 g : 1 mol = x : 4.82 mol
x = 70.9 g * 4.82 mol : 1 mol = 341.7 g
7 0
4 years ago
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