Answer is: concentration of hydronium ions is 5,5·10⁻⁸ M. [OH⁻] = 1,83·10⁻⁷ M; equilibrium concentration. The Kw (the ionic
product for water) at 25°C is 1·10⁻¹⁴ mol²/dm⁶ or 1·10⁻¹⁴ M².<span>
Kw = [H</span>₃O⁺] · [OH⁻]. [H₃O⁺] = Kw ÷ [OH⁻]. [H₃O⁺] = 1·10⁻¹⁴ M² ÷ 1,83·10⁻⁷ M. [H₃O⁺] = 5,5·10⁻⁸ M.
This problem requires using the concept of pH and pOH. The “p”
stands for the negative log so pH and pOH represent the negative log of the
concentration of hydrogen or hydroxide ions.
